481.Consider the following reaction and statements : [Co(NH3)4Br2]+ + Br– → [Co(NH3)3Br3] + NH3 (I) Two isomers are produced if the reactant complex ion is a cis-isomer. (II) Two isomers are produced if the reactant complex ion is a tran-isomer. (III) Only one isomer is produced if the reactant complex ion is a trans-isomer. (IV) Only one isomer is produced if the reactant complex ion is a cis-isomer. The correct statements are :- (1)(III) and (IV)
- (2)(II) and (IV)
- (3)(I) and (II)
- (4)(I) and (III)
482.A group of atoms can function as a ligand only when- (1)it is a small molecule
- (2)it has an unshared electron pair
- (3)it is a negatively charged ion
- (4)it is a positively charged ion.
483.The IUPAC name of K3Fe(CN)6 is :- (1)Potassium hexacyanoferrate(II)
- (2)Potassium hexacyanoferrate(III)
- (3)Potassium hexacyanoiron(II)
- (4)Tripotassium hexacyanoiron(II)
484.Observe the following complexes (Mn(CN)6)3−,(Fe(CN)6)−3,(Co(C2O4)3)3−,(MnCl6)3−,(Fe(CN)6)4−,(CoF6)3− From the above, the number of inner orbital complexes with paramagnetic nature is- (1)2
- (2)1
- (3)3
- (4)4
485.Which of the following will show optical isomerism ?- (1)[Cu(NH3)4]2+
- (2)[ZnCl4]2–
- (3)[Cr(C2O4)3]3–
- (4)[Co(CN)6]3–
486.The correct order of ligands arranged in increasing field strength.- (1)F−<Br−<I−<NH3
- (2)Br−<F−<H2O<NH3
- (3)H2O<−OH<CN−<NH3
- (4)Cl−<−OH<Br−<CN−
487.According to valence bond theory the metal atom or ion can make use of which of the following orbitals to yield hybrid orbitals, that can form bonds with ligands.- (1)(n−1)d,(n−1)s,np
- (2)( n−1)d,ns,np
- (3)(n−1)d, ns, (n-1)p
- (4)nd, (n-1)s, (n−1)p
488.The correct combination is :- (1)[NiCl4]2– – square-planar; [Ni(CN)4]2– – paramagnetic
- (2)[Ni(CN)4]2– – tetrahedral; [Ni(CO)4] – paramagnetic
- (3)[NiCl4]2– – paramagnetic; [Ni(CO)4] – tetrahedral
- (4)[NiCl4]2– – diamagnetic; [Ni(CO)4] – square-planar
489.sp3d2 hybridization is not displayed by :- (1)PF5
- (2)SF6
- (3)[CrF6]3–
- (4)BrF5
490.Which of the following statements are incorrect?(A) Co+3 with strong field ligand forms high magnetic moment complex.(B) For Co+3 if pairing energy (P)>Δ0 then the complex formed will have t2g4,eg2 configuration(C) For [Co(en)3]3+λabsorbed is less thenλabsorbed for [CoF6]3−(D) If Δ0=18000cm−1 for Co+3 then with same ligands for it Δt=16000cm−1- (1)A,D
- (2)B,C
- (3)A,B
- (4)A
491.Number of complexes from the following with even number of unpaired " d " electrons is (V(H2O)6)3+,(Cr(H2O)6)2+,(Fe(H2O)6)3+,(Ni(H2O)6)3+,(Cu(H2O)6)2+ [Given atomic numbers : V=23,Cr=24,Fe=26,Ni=28Cu=29 ]- (1)2
- (2)1
- (3)4
- (4)5
492.Addition of excess aqueous ammonia to a pink coloured aqueous solution of MCl2.6H2O (X) and NH4Cl gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1 : 3 electrolyte. The reaction of X with excess HCl at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for complex Y. Among the following options, which statement(s) is (are) correct?- (1)The hybridization of the central metal ion in Y is d2sp3
- (2)Addition of silver nitrate to Y gives only two equivalents of silver chloride
- (3)When X and Z are in equilibrium at 0ºC, the colour of the solution is pink
- (4)Z is a tetrahedral complex
493.Simplified absorption spectra of three complexes ((i), (ii) and (iii)) of Mnn+ ion are provided below; their λmax values are marked as A, B and C respectively. The correct match between the complexes and their λmax values is
(i) [M(NCS)6](−6+n) (ii) [MF6](−6+n) (iii) [M(NH3)6]n+- (1)A−(i),B−(ii),C−(iii)
- (2)A−(ii),B−(iii),C−(i)
- (3)A−(ii),B−(i),C−(iii)
- (4)A−(iii),B−(i),C−(ii)
494.For the square planar complex [M abcd] (where, M =central metal ; a, b, c and d are monodentate ligands) the number of possible geometrical isomers are- (1)1
- (2)2
- (3)3
- (4)4
495.Which statement is not true with respect to nitrate ion test ?- (1)A dark brown ring is formed at the junction of two solutions.
- (2)Ring is formed due to nitroferrous sulphate complex.
- (3)The brown complex is [Fe(H2O)5 (NO)]SO4.
- (4)Heating the nitrate salt with cone. H2S04, light brown fumes are evolved.
496.The order of energy absorbed which is responsible for the color of complexes A. (Ni(H2O)2(en)2)2+ B. (Ni(H2O)4(en))2+ and C. (Ni(en)3)2+ is- (1)B > A > C
- (2)A > B > C
- (3)C > B > A
- (4)C > A > B
497.The crystal field stabilisation energy (CFSE) for [CoCl6]4− is 18000 cm−1 The CFSE for [CoCl4]2− will be- (1)6000 cm−1
- (2)16000 cm−1
- (3)18000 cm−1
- (4)8000 cm−1
498.The hybridization and magnetic behaviour of cobalt ion in (Co(NH3)6)3+ complex, respectively is- (1)sp3d2 and diamagnetic
- (2)d2sp3 and paramagnetic
- (3)d2sp3 and diamagnetic
- (4)sp3d2 and paramagnetic
499.Match List I with List II List - IA. K2(Ni(CN)4)B. (Ni(CO)4)C. (Co(NH3)6)Cl3D. Na3(CoF6)List - III. sp3II. sp3d2III. dsp2IV. d2sp3 Choose the correct answer from the options given below:- (1)A-III, B-I, C-IV, D-II1
- (2)A-III, B-I, C-II, D-IV
- (3)A-I, B-III, C-II, D-IV
- (4)A-III, B-II, C-IV, D-I
500.Match the LIST-I with LIST-II (Complex/ Species) (Shape & magnetic moment)| LIST-I | LIST-II |
|---|
| A. (Ni(CO)4) | I. Tetrahedral, 2.8 BM | | B. (Ni(CN)4)2− | II. Square planar, 0 BM | | C. (NiCl4)2− | III. Tetrahedral, 0 BM | | D. (MnBr4)2− | IV. Tetrahedral, 5.9 BM | Choose the correct answer from the options given below:- (1)A-I, B-II, C-III, D-IV
- (2)A-IV, B-I, C-III, D-II
- (3)A-III, B-II, C-I, D-IV
- (4)A-III, B-IV, C-II, D-I
501.Which of the following complexes is used to be as an anticancer agent ?- (1)mer-[Co(NH3)3Cl]
- (2)Cis - [Pt Cl2(NH3)2]
- (3)cis - K2[Pt Cl2Br2]
- (4)Na2CoCl4
502.Match List – I with List - II List – I List - II(Complex) (Hybridisation & Magnetic characters) (A) (MnBr4)2− (I) d2s3& diamagnetic(B) (FeF6)3− (II) sp3d2& paramagnetic(C) (Co(C2O4)3)3− (III) sp3& diamagnetic(D) (Ni(CO)4) (IV) sp3& paramagneticChoose the correct answer from the options given below :- (1)(A) -(IV), (B) - (II), (C) - (I), (D) - (III)
- (2)(A) - (III), (B) - (I), (C) - (II), (D) - (IV)
- (3)(A) -(IV), (B) - (I), (C) - (II), (D) - (III)
- (4)(A) - (III), (B) - (II), (C) - (I), (D) - (IV)
503.An example of a sigma bonded organometallic compound is- (1)Ruthenocene
- (2)Grignard's reagent
- (3)Ferrocene
- (4)Cobaltocene
504.Which is diamagnetic?- (1)[Co(F)6]3−
- (2)[Ni(CN)4]2−
- (3)[NiC14]2−
- (4)[Fe(CN)6]3−
505.The following ligand is:- (1)hexadentate
- (2)tetradentate
- (3)bidentate
- (4)tridentate
506.The number of possible optical isomers for the complexes MA2B2 with sp3 and dsp2 hybridized metal atom, respectively, is :- (1)0 and 0
- (2)2 and 2
- (3)0 and 2
- (4)0 and 1
507.Match List - I with List - II. List - I (Complex)(A) (CoF6)3−(B) (NiCl4)2−(C) (Co(NH3)6)3+(D) (Ni(CN)4)2−List − II (Hybridisation of central metal ion)(I) d2sp3(II) sp3(III) sp3d2(IV) dsp2 Choose the correct answer from the options given below :- (1)(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
- (2)(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
- (3)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- (4)(A)-(III), (B)-(II), (C)-(I), (D)-(IV)
508.The total number of possible isomers for square-planar [Pt(Cl)(NO2)(NO3)(SCN)]2– is :- (1)8
- (2)12
- (3)16
- (4)24
509.A reaction of cobalt(III) chloride and ethylenediamine in a 1 : 2 mole ratio generates two isomeric products A (violet coloured) and B(green coloured). A can show optical activity, but, B is optically inactive. What type of isomers does A and B represent?- (1)Ionisation isomers
- (2)Linkage isomer
- (3)Coordination isomers
- (4)Geometrical isomers
510.Number of complexes which will exhibit synergic bonding amongst, [Cr(CO)6], [Mn(CO)5] and [Mn2(CO)10] is________.
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