91.Match List-I with List-II. List-I(A) Cd(s)+2Ni(OH)3(s)→CdO(s)+2Ni(OH)2(s)+H2O(l)(B) Zn(Hg)+HgO(s)→ZnO(s)+Hg(l)(C) 2PbSO4(s)+2H2O(l)→Pb(s)+PbO2(s)+2H2SO4(aq)(D) 2H2(g)+O2(g)→2H2O(l)List-II(I) Primary battery(II) Discharging of secondary battery(III) Fuel cell(IV) Charging of secondary Choose the correct answer from the options given below:- (1)(A) - (I), (B) - (II), (C) - (III), (D) - (IV)
- (2)(A) - (IV), (B) - (I), (C) - (II), (D) - (III)
- (3)(A) - (II), (B) - (I), (C) - (IV), (D) - (III)
- (4)(A) - (II), (B) - (I), (C) - (III), (D) - (IV)
92.The number of Faradays ( F ) required to produce 20 g of calcium from molten CaCl2 (Atomic mass of Ca=40gmol−1 ) is- (1)2
- (2)3
- (3)4
- (4)1
93.9.65C of electric current is passed through fused anhydrous magnesium chloride. The magnesium metal thus, obtained is completely converted into a Grignard reagent. The number of moles of the Grignard reagent obtained is- (1)5×10−4
- (2)1×10−4
- (3)5×10−5
- (4)1×10−5
94.The electrode potential of chlorine electrode is maximum, when the concentration of chloride ion in the solution (in molLL−1 ) is X. What is the value of X ?- (1)2.5×10−3
- (2)7.5×10−3
- (3)7.5×10−2
- (4)2.5×10−2
95.Λm∘ for NaCl, HCl and NaA are 126.4, 425.9 and 100.5 Scm2mol−1, respectively. If the conductivity of 0.001M HA is 5×10−5 Scm−1, degree of dissociation of HA is:- (1)0.50
- (2)0.25
- (3)0.125
- (4)0.75
96.Some statements about Lechlanche cell are (I) Anode is zinc metal (II) Cathode is graphite rod surrounded by powdered MnO2 and carbon (III)Electrolyte is a moist paste of ZnO and KOH (IV)Oxidation product is ZnO The correct statements are- (1)I & II only
- (2)II & III only
- (3)I & IV only
- (4)I, II & III only
97.In a typical fuel cell, the reactants (R) and product (P) are- (1)R=H2(g),O2(g);P=H2O(l)
- (2)R=H2(g),O2(g),Cl2(g);P=HClO4(aq)
- (3)R=H2(g),N2(g);P=NH3(qq)
- (4)R=H2(g),O2(g);P=H2O2(l)
98.The approximate time duration in hours to electroplate 30g of calcium from molten calcium chloride using a current of 5amp is [At. mass of Ca=40 ]- (1)8
- (2)80
- (3)10
- (4)16
99.The resistance of 0.01MKCl solution at 298K is 1500Ω. If the conductivity of 0.01M KCl solution at 298K is 0.1466×10−3Scm−1. The cell constant of the conductivity cell in (cm−1) is- (1)0.219
- (2)0.291
- (3)0.301
- (4)0.194
100.250 mL of a waste solution obtained from the workshop of goldsmith contains 0.1 M AgNO3 and 0.1 M AuCl. The solution was electrolyzed at 2V by passing a current of 1A for 15minutes. The metal/metals electrodeposited will be [EAg+|Ag0=0.80V,EAu+/Au0=1.69V]- (1)Silver and gold in equal mass proportion
- (2)Silver and gold in proportion to their atomic weights
- (3)Only gold
- (4)Only silver
101.Which of the following correctly represents Nernst equation? [P= products, R= reactants ]- (1)ΔG=ΔG∘+2.303RTlog[R][P]
- (2)ΔG=ΔG∘−2.303RTlog[R][P]
- (3)ΔG∘=ΔG+2.303RTlog[P][R]
- (4)ΔG∘=ΔG−2.303RTlog[P][R]
102.During galvanization of iron, which metal is used ion coating iron surface?- (1)Copper
- (2)Zinc
- (3)Nickel
- (4)Tin
103.Given: Co3++e−→Co2+;E0=+1.81V Pb4++2e−→Pb2+;Eo=+1.67V Ce4++e−→Ce3+;E∘=+1.61V Bi3++3e−→Bi;E∘=+0.20V oxidizing power of the species will increase in the order:- (1)Ce4+<Pb4+<Bi3+<Co3+
- (2)Bi3+<Ce4+<Pb4+<Co3+
- (3)Co3+<Ce4+<Bi3+<Pb4+
- (4)Co3+<Pb4+<Ce4+<Bi3+
104.The time required (in hours) to reduce 3mol of Fe3+ ions to Fe2+ ions with 2.0 amperes of current is (1F (=96500Cmol−1)- (1)30.2
- (2)40.2
- (3)10.2
- (4)15.2
105.The variation of λm of acetic acid with concentration is correctly represented as- (1)
- (2)
- (3)
- (4)
106.For the cell reaction 2Fe3+(aq)+2I−(aq)→2Fe2+(aq)+I2(aq) EcellΘ=0.24V at 298 K . The standard Gibbs energy (ΔrG⊖) of the cell reaction is [Given that Faraday constant F=96500Cmol−1 ]- (1)-46.32 kJ mol−1
- (2)-23.16 kJ mol−1
- (3)46.32kJmol−1
- (4)23.16kJmol−1
107.Calculate current in ampere required to deposit 4.8g Cu from its salt solution in 30 minutes. (Molar mass of Cu=63.5gmol−1 )- (1)8.1 ampere
- (2)6.4 ampere
- (3)10.5 ampere
- (4)12.3 ampere
108.The reduction potential of a half cell consisting of a Pt electrode immersed in 2.0MFe2+ and 0.02MFe3+ solution (in V) is Given (F2.303RT=0.059,EFe3+∣Fe2+0=0.771V)- (1)0.543
- (2)0.653
- (3)0.733
- (4)0.822
109.The reduction potential of hydrogen electrode at 25∘C in a neutral solution is (pH2=1) bar )- (1)0.059V
- (2)−0.059V
- (3)−0.413V
- (4)0.0V
110.Find the observed EMF of the cell Cd∣Cd2+(0.01M)∥ Cu2+(0.01M)∣Cu under conditions, internal resistance of 4Ω and producing a current of 0.15A. (Given, ECu2+/Cu∘=0.35V and E∘Cd2+/Cd=−0.4V )- (1)0.75V
- (2)0.15V
- (3)0.6V
- (4)0.9V
111.For hydrogen - oxygen fuel cell at one atm and 298KH2(g)+21O2(g)→H2O(l);ΔG∘=−240kJE∘ for the cell is approximately, (Given : F=96,500C )- (1)2.48V
- (2)1.24V
- (3)2.5V
- (4)1.26V
112.Given EFe+3/Fe+20=+0.76V and EI2/I−0=+0.55V. The equilibrium constant for the reaction taking place in galvanic cell consisting of above two electrodes is (F2.303RT=0.06)- (1)1×109
- (2)3×108
- (3)5×1012
- (4)1×107
113.38.6 amperes of current is passed for 100 seconds through an aqueous CuSO4 solution using platinum electrodes. The mass of copper consumed from the solution and volume of gas liberated at STP are respectively (molar mass of (Cu=63.54gmol−1).- (1)6.37g,0.448L
- (2)0.63g,0.224L
- (3)1.27g,0.224L
- (4)4g,0.448L
114.The product, which is not obtained during the electrolysis of brine solution is- (1)H2
- (2)HC1
- (3)NaOH
- (4)C12
115.What is the conductivity of 0.05MBaCl2 solution if its molar conductivity is 220Ω−1cm2mol−1 ?- (1)0.011Ω−1cm−1
- (2)0.033Ω−1cm−1
- (3)0.022Ω−1cm−1
- (4)0.044Ω−1cm−1
116.Calculate Ecello for Cd(s)(Cd++(1M)∥Ag+(1M))Ag(s) (ECdo=−0.403V;EAgo=0.799V)- (1)1.202V
- (2)−1.202V
- (3)0.396V
- (4)−0.396V
117.The Gibbs energy change (in J) for the given reaction at (Cu2+)=(Sn2+)=1M and 298 K is: Cu(s)+Sn2+(aq)→Cu2+(aq)+Sn(s)(ESn2O=−0.16V,ECu2+|Cu0=0.34V;TakeF=96500Cmol−1) 118.Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12. The current in Amperes used for the given electrolysis is . (Nearest integer). 119.0.2%(w/v) solution of NaOH is measured to have resistivity 870.0mΩm. The molar conductivity of the solution will be ×102mSdm2mol−1. (Nearest integer) 120.Consider the following reaction MnO4−+8H++5e−→Mn+2+4H2O,E°=1.51V The quantity of electricity required in Faraday to reduce five moles ofMnO4− is
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