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Set 19 of 25 · Questions 541-570 of 724

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JEE Main Chemistry · General Organic Chemistry · Set 19 (Q541-570)

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  1. 541.
    Among the following the strongest acid is :
    1. (1)CH3COOH
    2. (2)C6H5COOH
    3. (3)m-CH3OC6H4COOH
    4. (4)p-CH3OC6H4COOH
  2. 542.
    The major product obtained in the photo catalyzed bromination of 2-methylbutane is :
    1. (1)1-bromo-2-methylbutane
    2. (2)1-bromo-3-methylbutane
    3. (3)2-bromo-3-methylbutane
    4. (4)2-bromo-2-methylbutane
  3. 543.
    Hyperconjugation involves overlap of the following orbitals
    1. (1)σ–σ
    2. (2)σ–p
    3. (3)p – p
    4. (4)π – π
  4. 544.
    Tertiary alkyl halides are practically inert to substitution by SN2 mechanism because of :
    1. (1)steric hindrance
    2. (2)inductive effect
    3. (3)instability
    4. (4)insolubility
  5. 545.
    In sodium fusion test of organic compounds, the nitrogen of the organic
    compound is converted into
    1. (1)sodamide
    2. (2)sodium cyanide
    3. (3)sodium nitrite
    4. (4)sodium nitrate.
  6. 546.
    The carboxyl functional group (– COOH) is present in
    1. (1)picric acid
    2. (2)barbituric acid
    3. (3)ascorbic acid
    4. (4)aspirin
  7. 547.
    In the hydroboration-oxidation reaction of propene with diborane, and NaOH, the organic compound formed is :
    1. (1)OH
    2. (2)
    3. (3)OH
    4. (4)COH
  8. 548.
    Among the following acid which has the lowest value ?
    1. (1)COOH
    2. (2)CH–COOH
    3. (3)HCOOH
    4. (4)COOH
  9. 549.
    The major product formed when 1,1,1-trichloro-propane is treated with aqueous potassium hydroxide is:
    1. (1)Propyne
    2. (2)1-Propanol
    3. (3)2-Propanol
    4. (4)Propionic acid
  10. 550.
    Pyridine is less basic than triethylamine because :
    1. (1)Pyridine has aromatic character
    2. (2)Nitrogen in pyridine is sp2 hybridised
    3. (3)Pyridine is a cyclic system
    4. (4)In pyridine, lone pair of nitrogen is delocalise
  11. 551.
    Lassaigne’s test is used in qualitative analysis to detect
    1. (1)nitrogen
    2. (2)sulphur
    3. (3)chlorine
    4. (4)all of these
  12. 552.
    In Dumas method, of an organic compound gave of nitrogen at STP. The percentage of nitrogen is
    1. (1)16.9
    2. (2)18.7
    3. (3)23.2
    4. (4)29.6
  13. 553.
    Cyclohexene _______is type of an organic compound.
    1. (1)Benzenoid aromatic
    2. (2)Benzenoid non-aromatic
    3. (3)Acyclic
    4. (4)Alicyclic
  14. 554.
    Which of the following molecules represents the order of hybridisation
    from left to right atoms?
    1. (1)—
    2. (2)—
    3. (3)—
    4. (4) — —
  15. 555.
    The IUPAC name of the compound shown below is
    1. (1)2 - Bromo-6-chlorocyclohex-1-ene
    2. (2)6-Bromo-2-chlorocyclohexene
    3. (3)3-Bromo-1-chlorocyclohexene
    4. (4)1-Bromo-3-chlorocyclohexene
  16. 556.
    Arrange the following labelled hydrogens in decreasing order of acidity
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  17. 557.
    What is the product when acetylene reacts with hypochlorous acid ?
    1. (1)COCl
    2. (2)CHO
    3. (3)CHCHO
    4. (4)COOH.
  18. 558.
    The heating of phenyl-methyl ethers with HI produces
    1. (1)ethyl chlorides
    2. (2)iodobenzene
    3. (3)phenol
    4. (4)benzene
  19. 559.
    In which of the following compounds, the C–Cl bond ionisation shall give most stable carbonium ion ?
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  20. 560.
    The IUPAC name of the following compound is:
    1. (1)4-Hydroxyhept-6-en-1-yne
    2. (2)Hept-1-en-6-yn-4-ol
    3. (3)Hept-6-en-1-yn-4-ol
    4. (4)4-Hydroxyhept-1-en-6-yne
  21. 561.
    Which of the following represent the given mode of hybridisation ––sp–sp from left to right.
    1. (1)H2C=CH–C≡N
    2. (2)HC≡C–C≡CH
    3. (3)C=C=C=
    4. (4)
  22. 562.
    Identify the compound that exhibits tautomerism.
    1. (1)2-Butene
    2. (2)Lactic acid
    3. (3)2-Pentanone
    4. (4)Phenol
  23. 563.
    The molecular formula of second homologue in the homologous series of mono carboxylic acids is
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  24. 564.
    The IUPAC name of is
    1. (1)l‐bromo‐3‐methylbutane
    2. (2)2‐methyl‐3‐bromopropane
    3. (3)1‐bromopentane
    4. (4)2‐methyl ‐bromobutane.
  25. 565.
    In the following structure, the double bonds are marked as I, II, III and IV

    Geometrical isomerism is not possible at site (s) :
    1. (1)I
    2. (2)III
    3. (3)I and III
    4. (4)I and IV
  26. 566.
    Which of the following molecules represents the order of hybridization , , sp, sp from left to right atoms?
    1. (1)HC C – C CH
    2. (2)–CH = CH –
    3. (3) = CH – CH =
    4. (4) = CH – C CH
  27. 567.
    A straight chain hydrocarbon has the molecular formula . The
    hybridization of the carbon atoms from one end ofthe chain to the other are respectively and . The structural formula of the hydrocarbon would be
    1. (1)CHCH
    2. (2)CHCH
    3. (3)CHCH
    4. (4)CHCH
  28. 568.
    The increasing order of reactivity of the following compound towards reaction with alkyl halides directly is:
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  29. 569.
    The number of hybridised carbons in an acyclic neutral compound with molecular formula N is :
  30. 570.
    The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH is