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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Binomial Theorem · Set 13 (Q361-390)
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361.
5k5+3k3+157k is, if k∈N
(1)a natural number
(2)an integer
(3)a positive fraction
(4)equal to zero
362.
If (30C1)2+2(30C2)2+3(30C3)2+⋯+30(30C30)2=(30!)2α60!, then α is equal to
(1)30
(2)60
(3)15
(4)10
363.
If the fourth term in the binomial expansion of (x1+log10x1+x121)6 is equal to 200, and x>1, then the value of x is :
(1)100
(2)10
(3)103
(4)104
364.
If ∑i=120(20Ci+20Ci−120Ci−1)3=21k, then k equals :
(1)400
(2)50
(3)200
(4)100
365.
The total number of irrational terms in the binomial expansion of (71/5−31/10)60 is :
(1)55
(2)49
(3)48
(4)54
366.
If p and q are respectively the coefficient of x−3 and x−5 in the expansion of (x1/3+2x1/31)21,x>0, then 4q5p equal to
(1)102
(2)408
(3)182
(4)468
367.
∑k=0651−kC3 is equal to
(1)51C4−45C4
(2)51C3−45C3
(3)52C4−45C4
(4)52C3−45C3
368.
If the integer represented by 100! has K consecutive zeroes at the end, then K=
(1)24
(2)36
(3)64
(4)128
369.
Consider the following statements I : The number of non-trivial even divisors of the number 2α13α24α35α46α5, is (α1+1)(α2+1)(α3+1)(α4+1)(α5+1)−2 II : The number of non-trivial odd divisors of the number 2α1⋅3α2⋅4α3⋅5α4⋅6α5, is α2+α4+α5+α2α4+α4α5. Then
(1)I is false and II is false
(2)I is true and II is true
(3)I is false and II is true
(4)I is true and II is false
370.
xn+yn is divisible by
(1)x−y for all n∈N
(2)x+y for all n∈N
(3)x+y for all n=2m−1,m∈N
(4)x+y for all n=2m,m∈N
371.
A furniture manufacturer produces tables and bookshelves made up of wood and steel. The weekly requirement of wood and steel is given as below. Product Wood Steel Table (x) 8 2 Bookshelf (y) 11 3
The weekly availability of wood and steel is 450 and 100 units respectively. Profit on a table is ₹1000 and that on a bookshelf is ₹1200. To determine the number of tables and bookshelves to be produced every week in order to maximize the total profit, formulate the problem as L.P.P.
(1)Maximize Z=1000x+1200y Subject to 8x+11y≥450,2x+3y≤100,x≥0,y≥0
(2)Maximize Z=1000x+1200y Subject to 8x+11y≤450,2x+3y≤100,x≥0,y≥0
(3)Maximize Z=1000x+1200y Subject to 8x+11y≤450,2x+3y≥100,x≥0,y≥0
(4)Maximize Z=1000x+1200y Subject to 8x+11y≥450,2x+3y≥100,x≥0,y≥0
372.
The digit in the unit's place of 5834 is
(1)3
(2)5
(3)0
(4)1
373.
If n+11nCn+n1nCn−1+21nC1+nC0=101023 then n is equal to
(1)9
(2)8
(3)7
(4)6
374.
The remainder when 72022 + 32022 is divided by 5 is:
(1)0
(2)2
(3)3
(4)4
375.
The value of 50C4+∑r=1656−rC3 is :
(1)56 C4
(2)56 C3
(3)55C3
(4)55C4
376.
The smallest positive divisor greater than 1 of a composite number ' a ' is
(1)<a
(2)=a
(3)>a
(4)≤a
377.
If. the middle term in the expansion of (1+x)2n is the greatest term, then x lies in the interval
(1)(n+1n,nn+1)
(2)(nn+1,n+1n)
(3)(n−2,n)
(4)(n−1,n)
378.
The objective function of LPP defined over the convex set attains its optimum value at
(1)At least two of the corner points
(2)All the corner points
(3)At least one of the corner points
(4)None of the corner points
379.
The remainder when (11)1011 + (1011)11 is divided by 9 is
(1)1
(2)4
(3)6
(4)8
380.
The ten's digit in 1!+4!+7!+10!+12!+13 ! +15!+16!+17 ! is divisible by
(1)5
(2)7
(3)4
(4)3!
381.
The sum of all the coefficient in the binomial expansion of (1+2x)n is 6561 . Let R=(1+2x)n=I+F where I∈N and 0<F<1. If x=21, then 1−1+(2−1)4F=
(1)(32−4)
(2)4(32+4)
(3)(2−1)4
(4)1
382.
If C, denotes the binomial coefficient nCr, then (−1)C02+2C12+5C22+…+(3n−1)Cn2 is equal to
(1)(3n−2)2nCn
(2)(23n−2)2nCn
(3)(5+3n)2nCn
(4)(23n−5)2nCn+1
383.
Let nCr denote the binomial coefficient of xr inthe expansion of (1+x)n. If ∑k=010(22+3k)nCk=α.310+β.210,α,β∈then α+β is equal to
384.
For integers n and r, let (rn)={nCr,0,if n≥r≥0otherwise. The maximum value of k for which the sum ∑i=0k(i10)(k−i15)+∑i=0k+1(i12)(k+1−i13) exists, is equal to
385.
Let (kn) denote nCk and [nk]={(kn),0,if 0≤k≤notherwise. If Ak=∑i=09(i9)[1212−k+i]+∑i=08(i8)[1313−k+i] and A4−A3=190p, then p is equal to :
386.
Let n be a positive integer. Let A=∑k=0n(−1)knCk((21)k+(43)k+(87)k+(1615)k+(3231)k). If 63A=1−2301 then n is equal to
387.
Let f:R→R be a function defined as f(x)={3(1−2∣x∣),0,if ∣x∣≤2if ∣x∣>2 Let g:R→R be given by g(x)=f(x+2)−f(x−2) If n and m denote the number of points in R where g is not continuous and not differentiable, respectively, then n+m is equal to ____.
388.
∑k=13n6nC2k−1(−3)k is equal to :
389.
If 1+(2+49C1+49C2+...+49C49)(50C2+50C4+....+50C50) is equal to 2n.m, where m is odd, then n+ m is equal to_____
390.
Let α be the constant term in the binomial expansion of (x−x236)n,n≤15. If the sum of the coefficients of the remaining terms in the expansion is 649 and the coefficient of x−n is λα, then λ is equal to_________.