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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Binomial Theorem · Set 6 (Q151-180)
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151.
If the kth term in the expansion of (23x2−3x1)6 is independent of x, then the numerically greatest term in the expansion of (23x2−3x1)k when x=32, is
(1)8140
(2)(67)5
(3)2720
(4)(67)4
152.
The remainder, when 7103 is divided by 23, is equal to:
(1)6
(2)17
(3)9
(4)14
153.
If for some positive integer n, the coefficients of three consecutive terms in the binomial expansion of (1+x)n+5 are in the ratio 5:10:14, then the largest coefficientin this expansion is:
(1)252
(2)462
(3)792
(4)330
154.
If the coefficients of x9 and x10 in the binomial expansion of (3+2x)n are equal, then n=
(1)69
(2)96
(3)66
(4)99
155.
For z∈C, if (1+z)n=1+nC1z+nC2z2+….nCnzn and ∑r=0100100cr(sinrx)=(2cos2x)100sinkx, then k=
(1)25
(2)100
(3)50
(4)75
156.
If x is so small, that x5 and higher power of x may be neglected, then the coefficient of x4 in the expansion of x2+4−x2+9, is
(1)172819
(2)1728−19
(3)172843
(4)1728−43
157.
The number of terms in the expansion of (x2+y2)25−(x2−y2)25 after simplification is
(1)0
(2)26
(3)13
(4)50
158.
If rth and (r+1)th terms in the expansion of (p+q)n are equal, then r(p+q)(n+1)q is
(1)0
(2)1
(3)¼
(4)1/2
159.
The value of 1!50!1+3!48!1+5!46!1+……+49!2!1+51!1!1 is
(1)50!250
(2)51!250
(3)51!251
(4)50!251
160.
If |x|<1, then the coefficient of x5 in the expansion of (x−2)(x+1)3x is
(1)3233
(2)32−33
(3)3231
(4)32−31
161.
If k is the coefficient of x5 in the expansion of (2x2−3x31)5 then 23k=
(1)-20
(2)-40
(3)20
(4)40
162.
The remainder when 3100×250 is divided by 5 is
(1)3
(2)4
(3)1
(4)2
163.
The remainder when 32022 is divided by 5 is
(1)1
(2)2
(3)3
(4)4
164.
The number of integral terms in the expansion of (521+781)1016 is:
(1)127
(2)128
(3)130
(4)129
165.
The value of 10C1+10C2+10C3+….+10C9 is
(1)210−1
(2)210
(3)211
(4)210−2
166.
The middle term of expansion (x10+10x)10 is
(1)8C5
(2)10C5
(3)7C5
(4)9C5
167.
The least positive integer x satisfying 22010≡3x(mod5) is
(1)4
(2)3
(3)2
(4)1
168.
The value of (030)(1030)−(130)(1130)+(230)(1230)−⋯+(2030)(3030) is :
(1)60C20
(2)30C10
(3)30C15
(4)None of these
169.
Assertion (A) : If |x|<1, then ∑(−1)nxn+1=x+1x Reason (R): If |x|<1, then (1+x)−1 =1−x+x2−x3+… Which one of the following is true?
(1)(A) and (R) are true, (R) is a correct explanation of (A)
(2)(A) and (R) are true but (R) is not a correct explanation of (A)
(3)(A) is true, but (R) is false
(4)(A) is false but (R) is true
170.
If the number of integral terms in the expansion of (321+581)n is exactly 33, then the least value of n is:
(1)264
(2)128
(3)256
(4)248
171.
The term independent of x in the expansion of ((x2/3+1−x1/3)(x+1)−(x−x1/2)(x−1))10,x>1, is:
(1)240
(2)120
(3)150
(4)210
172.
Suppose 2−p,p,2−α,α are the coefficient of four consecutive terms in the expansion of (1+x)n. Then the value of p2−α2+6α+2pequals
(1)4
(2)10
(3)8
(4)none of these
173.
If n is the number of irrational terms in theexpansion of (31/4+51/8)60, then (n−1) is divisible by:
(1)26
(2)30
(3)8
(4)7
174.
Suppose A and B are the coefficients of 30th and 12th terms respectively in the binomial expansion of (1+x)2n−1. If 2A=5B, then n is equal to:
(1)22
(2)20
(3)21
(4)19
175.
In the expansion of (1+x)(1−x2)(1+x3+x23+x31)5,x=0, the sum of the coefficient of x3 and x−13 is equal to_______
176.
The coefficient of x−6, in the expansion of (54x+2x25)9, is ___________
177.
The term independent of x in the expansion of (x2/3−x1/3+1x+1−x−x1/2x−1)10, where x=0,1 is equal to
178.
If ∑r=052r+211C22r=nm,gcd(m,n)=1, then m−n is equal to .
179.
The remainder, when 7103 is divided by 17, is
180.
If the coefficient of x10 in the binomial expansion of (541x+x315)60 is 5kl, where l,k∈n and l is prime to 5, then k is equal to_____.