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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Binomial Theorem · Set 9 (Q241-270)
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241.
In solving the LPP : "minimize f=6x+10y subject to constraints x≥6, y≥2,2x+y≥10,x≥0,y≥0 " redundant constraints are
(1)x≥6,y≥2
(2)2x+y≥10,x≥0,y≥0
(3)x≥6
(4)none of these
242.
The digit in the unit place of the number 2009!+37886 is
(1)1
(2)9
(3)7
(4)3
243.
The value of 51100C50+52100C51+…+101100C100 is :
(1)1002101
(2)1002100
(3)1012101
(4)1012100
244.
If (n – 1)Cr = (k2 – 3) nCr+1, then an interval in which k lies is
(1)(2, ∞)
(2)(– ∞, – 2)
(3)(−3,3)
(4)(3,2)
245.
The greatest value of x satisfying 21≡385(modx) and 587≡167(modx) is
(1)32
(2)156
(3)56
(4)28
246.
Let Sn=1+q+q2+…+qn and Tn=1+(2q+1)+(2q+1)2+…+(2q+1)nwhere q is a real number and q=1. If 101C1+101C2.S1+…+101C101.S100=αT100, then α is equal to :
(1)299
(2)202
(3)200
(4)2100
247.
The sum of the series 20C0 – 20C1 + 20C2 – 20C3 + ..... + 20C10 is
(1)–20C10
(2)2120C10
(3)0
(4)20C10
248.
If x=2!32.5+3!322.5.7+4!332⋅5⋅7⋅9+…, then x2+8x+8=
(1)108
(2)54
(3)100
(4)144
249.
If {p} denotes the fractional part of the number p, then {83200} is equal to
(1)85
(2)81
(3)87
(4)83
250.
If the coefficients of x4,x5 and x6 in the expansion of (1+x)n are in the arithmetic progression, then th maximum value of n is:
(1)7
(2)21
(3)28
(4)14
251.
The sum of the co-efficient all even degree terms in x in the expansion of (x+x3−1)6+(x−x3−1)6,(x>1) is equal to :
(1)29
(2)32
(3)26
(4)24
252.
In the expansion of (53+32)15
(1)Number of rational terms is 3
(2)Sum of all rational terms is 58
(3)Sum of all rational terms is greater than the sum of all irrational terms
(4)Sum of all irrational terms is greater than the sum of all rational terms
253.
If (2−5x)5−1=a0+a1x+a2x2+…, then a2a1=
(1)31
(2)−32
(3)−31
(4)32
254.
Let x be a real number and −2<x<2. When (x+3)(x−2)x+1 is expanded in powers of x, then the coefficient of x3 is
(1)−129655
(2)−21697
(3)−21613
(4)−1800119
255.
The sum of the coefficients of x499 and x500 in (1+x)1000+x(1+x)999+x2(1+x)998+…+x1000 is :
(1)1002C500
(2)1002C501
(3)1001C501
(4)1000C501
256.
Let m and n be the coefficients of seventh and thirteenth terms respectively in the expansion of (31x31+2x321)18. Then (mn)31 is :
(1)94
(2)91
(3)41
(4)49
257.
The coefficient of the highest power of x in the expansion of (x+x2−1)8+(x−x2−1)8 is
(1)64
(2)128
(3)256
(4)512
258.
If the term independent of x in the expansion of (23x2−3x1)9 is k then 18k is equal to:
(1)9
(2)11
(3)5
(4)7
259.
n−1Cr=(k2−8)nCr+1 if and only if :
(1)22<k≤3
(2)23<k≤32
(3)23<k<33
(4)22<k<23
260.
The sum of all possible values of n∈N, so that the coefficients of x,x2 and x3 in the expansion of (1+x2)2(1+x)n, are in arithmetic progression is :
(1)12
(2)7
(3)3
(4)9
261.
n5−5n3+4n is divisible by 120 is true for
(1)all positive integers n
(2)all positive integers for n≥3 only
(3)all positive integers for n≥1 only
(4)all positive integers for n≥5 only
262.
Let (1+x+x2)10=a0+a1x+a2x2+…+a20x20. If (a1+a3+a5+…+a19)−11a2=121k, then k is equal to _____.
263.
Let (2x2+3x+4)10=∑r=020arxr Then a13a7 is equal to
264.
The ratio of the coefficient of the middle term in the expansion of (1+x)20and the sum of the coefficients of two middle terms in expansion of (1+x)19 is
265.
If Cr=25Cr and C0+5⋅C1+9⋅C2+…+(101)⋅C25=225⋅k then k is equal to
266.
If the Coefficient of x30 in the expansion of (1+x1)6(1+x2)7(1−x3)8;x=0 is α, then |α| equals
267.
The sum of the series 2×1×20C4−3×2×20C5+4×3×20C6−5×4×20C7+…+18×17×20C20, is equal to _______.
268.
Let the coefficient of xr in the expansion of (x+3)n−1+(x+3)n−2(x+2)+(x+3)n−3(x+2)2+…⋯+(x+2)n−1 be αr. If ∑r=0nαr=βn−γn,β,γ∈N, then the value of β2+γ2 equals
269.
If the co-efficient of x7 and x8 in the expansion of (2+3x)nare equal, then the value of n is equal to ___
270.
Let the sum of the coefficients of the first three terms in the expansion of (x−x23)n, x=0,nϵN, be 376. Then the coefficient of x4 is ________