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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Complex Numbers · Set 3 (Q61-90)
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61.
The modulus of the conjugate of z=(1−2i)2−2+i is
(1)51
(2)51
(3)251
(4)5
62.
3+i(1+i)x−2i+3−i(2−3i)y+i=i⇒x+y=
(1)-1
(2)1
(3)-2
(4)2
63.
If x+iy=(−1+i3)2010, then x=
(1)22010
(2)−22010
(3)-1
(4)1
64.
Let C be the circle in the complex plane with centre z0=21(1+3i) and radius r = 1. Let z1 = l + i and the complex number z2 be outside circle C such that (z1−z0)(z2−z0)=1. If z0,z1 and z2 are collinear, then the smaller value of (z2)2 is equal to
(1)25
(2)27
(3)213
(4)23
65.
If α,β,γ,δ are the roots of the equation x4 + x3 + x2 + x +1 = 0, then α2021+β2021+γ2021+δ2021
(1)- 4
(2)-1
(3)1
(4)4
66.
Let A=(θ∈(−2π,π):1−2isinθ3+2isinθispurelyimaginary). Then the sum of the elements in A is:
(1)65π
(2)π
(3)43π
(4)32π
67.
The modulus and amplitude of 1−(1−i)21+2i are
(1)2 and 6π
(2)1 and 0
(3)1 and 3π
(4)1 and 4π
68.
If 13eitan−1125=a+ib, then the ordered pair (a,b)=
(1)(12,5)
(2)(5,12)
(3)(24,10)
(4)(10,24)
69.
If the point (kk−1,kk−2) lies on the locus of z satisfying the inequality 3z+iz+3i<1, then the interval in which k lies is
(1)(−∞,2)∪(3,∞)
(2)[2,3]
(3)[1,5]
(4)(−∞,1)∪(5,∞)
70.
If z = 0 be a complex number such that (z−z1)=2, then the maximum value of |z| is:
(1)2
(2)1
(3)2−1
(4)2+1
71.
If z = x + iy satisfies |z| - 2 = 0 and |z-i|-|z+5i|=0, then
(1)x + 2y - 4 = 0
(2)x2 + y - 4 = 0
(3)x + 2y + 4 = 0
(4)x2- y + 3 = 0
72.
If α and β are the roots of x2+x+1=0, then α16+β16=
(1)2
(2)0
(3)1
(4)-1
73.
If ω is a complex cube root of unity, then (1−ω+ω2)6+(1−ω2+ω)6=
(1)0
(2)6
(3)64
(4)128
74.
(−i+3)300+(−i−3)300=
(1)2300
(2)2301
(3)2100
(4)−2300
75.
If 1,α1,α2,α3 and α4 are the roots of z5−1=0 and ω is a cube roots of unity, then (ω−1)(ω−α1)(ω−α2)(ω−(α3)(ω−α4)+ω is equal to
(1)0
(2)-1
(3)-2
(4)1
76.
If α,β are non-real cube roots of 2, then α6+β6 equals
(1)8
(2)4
(3)2
(4)1
77.
If log31(2+|z||z|2−|z|+1)>−2, then z lies inside
(1)a triangle
(2)an ellipse
(3)a circle
(4)a square
78.
Let α and β be the roots of the equation x2+(2i−1)=0. Then, the value of ∣α8+β8∣ is equal to:
(1)50
(2)250
(3)1250
(4)1500
79.
If a,−a,b are the roots of x3−5x2−x+5=0, then b is a root of
(1)x2−5x+10=0
(2)x2+3x−20=0
(3)x2+5x−30=0
(4)x2−3x−10=0
80.
If z is a complex number such that |z+4|≥3, then the smallest value of |z+3| is
(1)3
(2)1
(3)2
(4)0
81.
If z+αz−α(α∈R) is a purely imaginary number and ∣z∣=2, then a value of α is :
(1)2
(2)1
(3)21
(4)2
82.
If a>0 and z=x+iy, then logcos2θ|z−a|>logcos2θ|z−ai|,(θ∈R) implies
(1)x>y
(2)x<y
(3)x+y=cosθ
(4)x+y<0
83.
(1−i)2014(1+i)2016 is equal to
(1)−2i
(2)2i
(3)2
(4)-2
84.
Let z be a complex number such that the real part of z+2iz−2i is zero. Then, the maximum value of |z−(6+8i)| is equal to
(1)12
(2)10
(3)8
(4)∞
85.
The solutions of the equation z2(1−Z2)=16,z∈C, lie on the curve
(1)|z|=1
(2)|z|=2|z|
(3)|z|2=3|z|+2
(4)|z|=2
86.
If α and β are the roots of the equation 2z2−3z−2i=0, where i=−1, then 16Re(α15+β15α19+β19+α11+β11)⋅lm(α15+β15α19+β19+α11+β11) is equal to
(1)441
(2)398
(3)312
(4)409
87.
If the least and the largest real values of α, for which the equation z+α|z−1|+2i=0(z∈C and i=−1) has a solution, are p and q respectively; then 4(p2+q2) is equal to
88.
For a complex number z, let Re(z) denote the real part of z. Let S be the set of all complex numbers z satisfying z4−|z|4=4iz2, where i=−1. Then, the minimum possible value of (z1−z2)2, where z1,z2∈S with Re(z1)>0 and Re(z2)<0 is [2020 Adv.]
89.
If z1=a+ib and z2=c+id are complex numbers such that ∣z1∣=∣z2∣=1 and R(z1zˉ2)=0, then the pair of complex numbers w1=a+ic and w2=b+id, Find R(w1wˉ2)
90.
If (1−i1+i)2m=(i−11+i)3n=1,(m,n∈N)then the greatest common divisor of the least values of m and nis