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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Complex Numbers · Set 6 (Q151-180)
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151.
For n∈N, If An=cos(2nπ)+isin(2nπ), then (A1A2A3A4)4=
(1)2−1−i
(2)1
(3)0
(4)21−i
152.
All the points in the set S=(α−iα+i:α∈R)(i=−1) lie on a :
(1)straight line whose slope is 1.
(2)circle whose radius is 1.
(3)circle whose radius is 2.
(4)straight line whose slope is −1.
153.
For two non – zero complex number z1 and z2, if Re(z1z2)=0 and Re(z1+z2)=0, then which of the following are possible? (A) Imz1>0 and Imz2>0 (B) Im(z1)<0 and Imz2>0 (C)Imz1>0 and Im(Z2)<0 (D) Im(Z1)<0 and Im(z2)<0 Choose the correct answer from the options given below:
(1)B and D
(2)B and C
(3)A and B
(4)A and C
154.
If the complex cube roots of (−i) are α,β,γ, then α2+β2+γ2=
(1)1
(2)-1
(3)−i
(4)0
155.
If z is a complex number, then the number of common roots of the equation z1985+z100+1=0 and z3+2z2+2z+1=0, is equal to:
(1)1
(2)2
(3)0
(4)3
156.
If z=x−iy and z31=a+ib, then a2+b2(ax+by)=
(1)-2
(2)-1
(3)1
(4)2
157.
Let w1 be the point obtained by the rotation of z1 = 5 + 4i about the origin through a right angle in the anticlockwise direction, and W2 be the point obtained by the rotation of z2 = 3 + 5i about the origin through a right angle in the clockwise direction. Then the principal argument w1 - w2 is equal to
(1)π−tan−198
(2)−π+tan−1533
(3)−π+tan−198
(4)π−tan−1533
158.
If the cube roots of unity are 1,ω,ω2, then the roots of the equation (x−1)3+8=0, are:
(1)−1,1+2ω,1+2ω2.
(2)−1,1−2ω,1−2ω2.
(3)−1,−1,−1.
(4)−1,−1+2ω,−1−2ω2.
159.
If the equation, x2+bx+45=0(b∈R) has conjugate complex roots and they satisfy |z+1|=210 then:
(1)b2+b=12
(2)b2−b=30
(3)b2−b=36
(4)b2+b=30
160.
If z1,z2 are complex numbers such that Re(z1)=|z1−1|,Re(z2)=|z2−1| and arg(z1−z2)=6π then Im(z1+z2) is equal to
(1)23
(2)31
(3)32
(4)23
161.
Let complex numbers α and α1 lies on circles (x−x0)2+(y−y0)2=r2 and (x−x0)2+(y−y0)2=4r2, respectively. If z0=x0+iy0 satisfies the equation 2(z0)2=r2+2, then |α|=
(1)21
(2)21
(3)71
(4)31
162.
If 1,ω,ω2,…,ω8 are the roots of the equation x9−1=0, then ∑r=18(ωr)99=
(1)0
(2)8
(3)1
(4)ω
163.
If z=x+iy, xy=0, satisfies the equation z2+izˉ=0, then ∣z2∣ is equal to :
(1)9
(2)1
(3)4
(4)41
164.
For real numbers a and b, if 4a+i(3a−b)=b−6i and z=a+4bi, then a|z|=
(1)22
(2)62
(3)2
(4)2
165.
Let S be the set of all complex numbers z satisfying ∣z2+z+1∣=1. Then, which of the following statements is/are true? [2020 Adv.]
(1)|z+1/2|≤1/2,∀ z∈S
(2)∣z∣≤2,∀z∈S
(3)|z+1/2|≥1/2,∀ z∈S
(4)The set S has exactly four elements
166.
If z1=(2,−1) and z2=(6,3), then amp(z1+z2z1−z2)=
(1)−43π−tan−1(41)
(2)4πtan−1(41)
(3)43π+tan−1(41)
(4)4π+tan−1(41)
167.
The value of (1+i+11)21+i3 is
(1)20
(2)9
(3)45
(4)54
168.
If z is a complex number with ∣z∣≥5. Then the least value of z+z2 is
(1)524
(2)526
(3)523
(4)529
169.
If i=−1 then ∑n=0∞(3i)n=
(1)109−3i
(2)9−3i
(3)9+3i
(4)109+3i
170.
If the roots of the equation x3+ax2+bx+c=0 are in A.P., then 2a3−9ab=
(1)9c
(2)18c
(3)27c
(4)−27c
171.
(−3+4i)(8+6i)=
(1)±(1+2i)
(2)±(3+i)
(3)±(1+7i)
(4)±(7−i)
172.
If P is a complex number whose modulus is one, then the equation (1−iz1+iz)4=P has
(1)real and equal roots
(2)real and distinct roots
(3)two real and two complex roots
(4)all complex roots
173.
If a>0 and z=a−i(1+i)2, has magnitude 52, then z is equal to:
(1)−51−53i
(2)−53−51i
(3)51−53i
(4)−51+53i
174.
If z=23+2i(i=−1), then (1+iz+z5+iz8)9 is equal to :
(1)0
(2)1
(3)−1+2i9
(4)−1
175.
If z=eiθ and 3sin3θ+2sin2θ+5sin5θ3cos3θ+2cos2θ+5cos5θ=∑r=010brzri∑r=010arzr then 10(∑r=010ar+∑r=010br)=
(1)0
(2)1
(3)2
(4)3
176.
If α is a complex number satisfying the equation α2+α+1=0 then α31 is equal to
(1)1
(2)0
(3)α
(4)α2
177.
The imaginary part of(3+2−54)1/2−(3−2−54)1/2 can be:
(1)6
(2)−6
(3)−26
(4)2
178.
The equation of a circle is Re(z2) + 2(Im(z))2 + 2Re(z) = 0, where z = x+iy A line which passes through the center of the given circle and the vertex of the parabola, x2 − 6x − y + 13 = 0, has y-intercept equal to ___
179.
If 1,ω,ω2,ω3……,ωn−1 are the n,nth roots of unity, then (1−ω)(1−ω2)…..(1−ωn−1) equal M. Find M/n.
180.
Let A=z∈C:|z-2-i|=3, B=z∈C:Re(z-iz)=2 and S=A∩B. Then ∑|z|2 is equal to ____.