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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Continuity & Differentiability · Set 9 (Q241-270)
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241.
The constant ' c ' of Lagrange's mean value theorem for the function f(x)=4x−12x+3 defined on [1,2] is
(1)31+15
(2)41+21
(3)35
(4)23
242.
An enemy fighter jet is flying along the curve given by y=x2+2. A soldier is placed at (3,2) wants to shoot down the jet when it is nearest to him. Then the nearest distance is
(1)2 units
(2)3 units
(3)5 units
(4)6 units
243.
If f(x)=(xsinx1−cosKx,ifx=021,ifx=0) is continuous at x=0, then the value of K is
(1)0
(2)±2
(3)±1
(4)±12
244.
f(x)={2−1+cosx72x−9x−8x+1,Klog2log3,x=0x=0 Find the value of k for which the function f is continuous.
(1)2
(2)24
(3)183
(4)242
245.
Let f be any function defined on R and let it satisfy the condition: |f(x)−f(y)|≤((x−y)2),∀(x,y)∈R Iff(0)=1, then:
(1)f(x)<0,∀x∈R
(2)f(x) can take any value in R
(3)f(x)=0,∀x∈R
(4)f(x)>0,∀x∈R
246.
If y=(tan−1x)2, then (x2+1)2dx2d2y+2x(x2+1)dxdy=
(1)4
(2)2
(3)1
(4)0
247.
Let f(x)=ax3+bx2+cx+41 be such that f(1)=40, f′(1)=2 and f′′(1)=4. Then a2+b2+c2 is equal to:
(1)73
(2)62
(3)51
(4)54
248.
Let y=f(x)=sin3(3π(cos(32π(−4x3+5x2+1)23))), then at x=1,
(1)2y’+3π2y=0
(2)2y’+3π2y=0
(3)2y’−3π2y=0
(4)y’+3π2y=0
249.
The range of the real valued function f(x)=9−x2 is
(1)[−3,3]
(2)[−3,0]
(3)[0,3]
(4)[−2,2]
250.
The approximate value of log10998 is (given that log10e=0.4343 )
(1)3.0008686
(2)1.9991314
(3)2.0008686
(4)2.9991314
251.
The number of points in (– ∞, ∞), for which x2 – x sinx – cosx = 0, is
(1)6
(2)4
(3)2
(4)0
252.
The function f(x)={4π+tan−1x,21(∣x∣−1),∣x∣≤1∣x∣>1 is:
(1)both continuous and differentiable on R−(−1)
(2)both continuous and differentiable on R−(1)
(3)continuous on R−(−1) and differentiable on R−(−1,1)
(4)continuous on R−(1) and differentiable on R−(−1,1)
253.
Let f(x)=⎩⎨⎧x−[x]sin(x−[x]),max{2x,3[∣x∣]},1,x∈(−2,−1)∣x∣<1otherwise where [t] denotes greatest integer ≤ t. If m is the number of points where f is not continuous and n is the number of points where f is not differentiate, then the ordered pair (m, n) is :
(1)(3, 3)
(2)(2, 4)
(3)(2, 3)
(4)(3, 4)
254.
Let f, g : [–1, 2] → R be continuous function which are twice differentiable on the interval (–1, 2). Let the values of f and g at the points –1, 0 and 2 be as given in the following table :
In each of the intervals (–1, 0) and (0, 2) the function (f – 3g)" never vanishes. Then the correct statement(s) is (are)
(1)f'(x) – 3g'(x) = 0 has exactly three solutions in (–1, 0) ∪ (0, 2)
(2)f'(x) – 3g'(x) = 0 has exactly one solution in (–1, 0)
(3)f'(x) – 3g'(x) = 0 has exactly one solution in (0, 2)
(4)f'(x) – 3g'(x) = 0 has exactly two solutions in (–1, 0) and exactly two solutions in (0, 2)
255.
Let the function f(x)=(x2+1)(x2−ax+2)+cos|x| be not differentiable at the two points x=α=2 and x=β. Then the distance of the point (α,β) from the line 12x+5y+10=0 is equal to:
(1)5
(2)4
(3)3
(4)2
256.
If f(x)=Max3-x,3+x,6 is not differentiable at x=a, and x=b, then |a|+|b|=
(1)4
(2)5
(3)6
(4)8
257.
If x = –1 and x = 2 are extreme points of f(x) = αlog|x| + βx2 + x then :
(1)α = 2, β =−21
(2)α = 2, β = 21
(3)α = –6, β = 21
(4)α = –6, β = –21
258.
A wire of length 20cm is bent in the form of a sector of a circle. The maximum area that can be enclosed by the wire is
(1)25sq.cm
(2)20 sq. cm
(3)30sq⋅cm
(4)10 sq. cm
259.
Consider the function f:(0,2)→R defined by f(x)=2x+x2 and the function g(x) defined by g(x)=(minf(t),0<t≤xand0<x≤123+x,1<x<2). Then
(1)g is continuous but not differentiable at x=1
(2)g is not continuous for all x∈(0,2)
(3)g is neither continuous nor differentiable at x=1
(4)g is continuous and differentiable for all x∈(0,2)
260.
If 2xy + 3yx = 20, then dxdy at (2, 2) is equal to:
(1)−(3+loge42+loge8)
(2)−(4+loge83+loge16)
(3)−(2+loge43+loge8)
(4)−(2+loge83+loge4)
261.
The range of the real valued function f(x)=x−|x|1 is
(1)(0,∞)
(2)(−∞,0)
(3)(−∞,0)∪(0,∞)
(4)(−∞,∞)
262.
Let f(x)=aaxax2−1aax0−1a,a∈R. Then the sum of which the squares of all the values of a for 2f'(10)-f'(5)+100=0 is:
(1)117
(2)106
(3)125
(4)136
263.
Let f(x)=(2x2+5)∣x∣−3,x∈R. If m and n denote the number of points where f is not continuous and not differentiable respectively, then m+n is equal to :
(1)5
(2)2
(3)0
(4)3
264.
Let [x] denote the greatest integer function, and let m and n respectively be the numbers of the points, where the function f(x)=[x]+|x−2|,−2<x<3, is not continuous and not differentiable. Then m+n is equal to:
(1)6
(2)8
(3)9
(4)7
265.
Let f:R→R satisfy f(x + y) = 2xf(y) + 4yf(x),∀x,y∈R. If f(2) = 3, then 14. f′(2)f′(4) is equal to_____.
266.
The minimum value of α for which the equation sinx4+1−sinx1=α has at least one solution in (0,2π) is
267.
Let m and n be two positive integers greater than 1. If limα→0(αmecos(αn)−e)=−(2e), then nm the value of is
268.
The maximum value of the function f(x) = 2x3 – 15x2 + 36x – 48 on the set A = {x |x2 + 20 ≤ 9x} is
269.
Let [x] be the greatest integer ≤ x. Then the number of points in the interval (-2, 1) where the function f(x)=∣[x]∣+x−[x] is discontinuous, is_____.
270.
If y(x)=(xxx),x>0 then dy2d2x+20 at x = 1 is equal to: