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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Differential Equations · Set 11 (Q301-326)
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301.
Let y=y(x) be the solution of the differential equation cosx(loge(cosx))2dy+(sinx−3ysinxloge(cosx))dx=0,x∈(0,2π). If y(4π)=loge2−1, then y(6π) is equal to:
(1)loge(3)−loge(4)1
(2)loge(3)−loge(4)2
(3)loge(4)−loge(3)1
(4)−loge(4)1
302.
Let y=y(x) be the solution of the differential equation, xdxdy+y=xlogex,(x<1). If 2y(2)=loge4−1,then y(e) is equal to :
(1)−2e
(2)−2e2
(3)4e
(4)4e2
303.
Solution of edxdy=x when x=1 and y=0 is
(1)y=x(logx−1)+1
(2)y=x(logx−1)+4
(3)y=x(logx−1)+3
(4)y=x(logx+1)+1
304.
Statement I : The differential equation corresponding to the family of circles having their centres on Y-axis and fixed radius k is (x2−k2)(dxdy)2+x2=0 Statement II : The differential equation of corresponding to the family of circles passing through the origin and having their centres on X-axis is x2−y2+2xydxdy=0 Which of the above statements is (are) true?
(1)Statement I is true, but Statement II is false
(2)Statement II is true, but Statement I is false
(3)Both Statement I and Statement II are true
(4)Both Statement I and Statement II are false
305.
y=ax+b is
(1)General solution of dx3d3y=0
(2)General solution for dxdy=a+b
(3)General solution for both dx2d2y=0 and dx3d3y=0
(4)General solution for dx2d2y=0
306.
Let y=y1(x) and y=y2(x) be two distinct solutions of the differential equation dxdy=x+y, with y1(0)=0 and y2(0)=1 respectively. Then, the number of points of intersection of y=y1(x) and y=y2(x) is
(1)0
(2)1
(3)2
(4)3
307.
The general solution of the differential equation (x - y2)dx + y(5x + y2)dy = 0 is :
(1)(y2+x)4=C∣(y2+2x)3∣
(2)(y2+2x)4 = C|(y2+x)3|
(3)|(y2+x)3| = C(2y2+x)4
(4)|(y2+2x)3| = C(2y2+x)4
308.
If dxdy=y+3>0 and y(0) = 2, then y(ln2) is equal to :
(1)7
(2)5
(3)13
(4)–2
309.
If dxdy=2y2x+y−2x,y(0)=1, then y(1) is equal to :
(1)log2 (2 + e)
(2)log2 (1 + e)
(3)log2 (2e)
(4)log2 (1 + e2)
310.
If x = x(y) is the solution of the differential equation ydydx= 2x + y3 (y + 1)ey, x(1) = 0; then x(e) is equal to :
(1)e3(ee−1)
(2)ee(e3-1)
(3)e2(ee + 1)
(4)ee(e2-1)
311.
Let the solution curve of the differential equation xdxdy−y=y2+16x2,y(1)=3 be y=y(x). Then y(2) is equal to :
(1)15
(2)11
(3)13
(4)17
312.
The general solution of (1+eyx)dx+eyx(1−yx)dy=0
(1)yexy+x=c
(2)yeyx−x=c
(3)yeyx+y=c
(4)yeyx+x=c
313.
The general solution of the differential equation dxdy=6x−9y+72x−3y+5 is
(1)x−3y+322log∣3x−7∣+c=0
(2)x−3y+38log∣6x−9y−1∣+c=0
(3)3x−3y+38log∣3x−9y+1∣+c=0
(4)3x−2y+322log∣2x−3y−7∣+c=0
314.
If the general solution of dxdy=xy−y2−x2y2 is tan−1(xy)=f(y)+C, then f(e3)=
(1)0
(2)1
(3)2
(4)3
315.
The solution of the differential equation dxdy=(4x+y+1)2, when y(0)=1 is
(1)y=2x2−1−8π
(2)y=4x−(1+8π)
(3)y=2tan(2x+4π)−4x−1
(4)y=2tan(x+8π)+4x−1
316.
The solution of the differential equation xdxdy−y=3 represents a family of
(1)straight lines
(2)circles
(3)parabolas
(4)ellipses
317.
If the family of curves y=ae4x+be−x, where a,b are arbitrary constants represents the general solution of the differential equation f(x,ydxdy,dx2d2y)=0, then dxdf=
(1)dx2d2y−3dxdy−4y
(2)dx3d3y−3dx2d2y−4dxdy
(3)dx3d3y−dx2d2y−3dxdy+2
(4)dx3d3y−dx2d2y+3
318.
Find the solution of the following differential equation (xcos(xy)+ysin(xy))ydx=(ysin(xy)−xcos(xy))xdy
(1)ycos(yx)=±e−c
(2)xcos(xy)=±e−c
(3)xycos(xy)=±e−c
(4)xysin(xy)=±e−c
319.
The solution of dxdy=x−yx+y is
(1)tan−1(xy)=logx2+y2+C
(2)tan−1(xy)=logx2−y2+C
(3)sin−1(xy)=logx2+y2+C
(4)cos−1(xy)=logx2−y2+C
320.
The differential equaiton of the simple harmonic motion given by x=Acos(nt+α) is
(1)dt2d2x−n2x=0
(2)dt2d2x+n2x=0
(3)dtdx−dt2d2x=0
(4)dt2d2x−dtdx+nx=0
321.
The general solution of the differential equation (x−2y+1)dy−(3x−6y+2)dx=0 is
(1)(x+2y+53)2/25⋅e115(x+2y)=C
(2)(x−2y+53)2/25.e1/5(x−2y)=C
(3)(x−2y+53)2/25⋅e1/5(6x−2y)=C
(4)(x−2y+51)2/25⋅e1/5(x−2y)=C
322.
Match the differential equations in List-I to their integrating factors in List-II. List-I (Differential equation)(P)(x3+1)dxdy+x2y=3x2(Q)x2dxdy+3xy=x6(R)(x3+1)2dxdy+6x2(x3+1)y=x2(S)(x2+1)dxdy+4xy=lnxList-II (Integrating factor)(1)x3(2)(x3+1)2(3)(x2+1)2(4)x2+1(5)(x3+1)1/3(6)(x3+1)1/2 The correct answer is P Q R S
(1)4 1 2 3
(2)5 1 2 3
(3)5 2 3 6
(4)5 1 3 4
323.
Let f be a twice differentiable non-negative function such that (f(x))2=25+∑((f(t))2+(f’(t))2)dt. Then the mean of f(loge(1)),f(loge(2)),……,f(loge(625)) is equal to ____ .
324.
Let y=y(x) be the solution of the differential equation (x+y+2)2dx=dy,y(0)=−2. Let the maximum and minimum values of the function y=y(x) in (0,3π) be α and β, respectively. If (3α+π)2+β2=γ+δ3,γ,δ∈Z, then γ+δ equals________
325.
Let f be a real-valued differentiable function on R (the set of all real numbers) such that f(1)=1. If the y-intercept of the tangent at any point P(x, y) on the curve y = f(x) is equal to the cube of the abscissa of P, then the value of f(−3) is equal to
326.
Let y = y(x) be the solution of the differential equationdxdy=3xy2+x24y3+2yx2,y(l) = 1. If for some n∈N,y(2)∈[n−1,n), then n is equal to ________