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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Differential Equations · Set 9 (Q241-270)
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241.
The integrating factor of dxdy+y=x1+y is
(1)xex
(2)xe1/x
(3)xex
(4)exx
242.
The solution of the differential equation dx2d2y+y=0 is
(1)y=3sinx+4cosx
(2)y=x2
(3)y=x+2
(4)y=logx
243.
The general solution of the differential equation dxdy=x+y−7x+y−3 is
(1)(x+y−5)2=Cey+x
(2)(x+y−5)2=Cey−x
(3)2log(x+y−5)=3x+2y+C
(4)log(x+y−3)=3(x+y−2)2+C
244.
If y=(π2x−1)cosecx is the solution of the differential equation, dxdy+p(x)y=π2cosecx;0<x<2π, then the function p(x) is equal to:
(1)tanx
(2)cotx
(3)cosecx
(4)secx
245.
The general solution of the differential equation dx=(2x+3y−4)dy is
(1)2x+6y−3log∣4x+6y−5∣=c
(2)6y−3log|4x+6y−5|=c
(3)2x+6y−8−3log|4x+6y−5|=c
(4)6x+6y−3log∣4x+6y−5∣=c
246.
If m and n are respectively the order and degree of the differential equation of the family of parabolas with origin as its focus and X-axis as its axis, then mn−m+n=
(1)1
(2)2
(3)3
(4)4
247.
Solution of the differential equation 2ysinxdxdy=2sinxcosx−y2cosx satisfying y(π/2)=1 is given by
(1)y2=sinx
(2)y=sin2x
(3)y2=cosx+1
(4)y2sinx=4cos2x
248.
Let y=y(x) be the solution curve of the differential equation (1+x2)dy+(y−tan−1x)dx=0,y(0)=1. Then the value of y(1) is :
(1)eπ/44+2π−1
(2)eπ/42+4π−1
(3)eπ/42−4π−1
(4)eπ/44−2π−1
249.
If the solution curve of the differential equation (2x − 10y3) dy+ ydx= 0, passes through the points (0,1) and (2, β), then β is a root of the equation:
(1)y5 − 2y − 2 = 0
(2)2y5 − 2y − 1 = 0
(3)2y5 − y2 − 2 = 0
(4)y5 − y2 − 1 = 0
250.
Let the solution curve of the differential equation xdy=(x2+y2+y)dx, x > 0, intersect the line x = 1 at y = 0 and the line x = 2 at y = α. Then the value of α is :
(1)21
(2)23
(3)−23
(4)25
251.
Let x = x(y) be the solution of the differential equation 2yex/y2dx+(y2−4xex/y2)dy=0 such that x(1) = 0. Then, x(e) is equal to
(1)eloge(2)
(2)-eloge(2)
(3)e2loge(2)
(4)-e2loge(2)
252.
Let y = y(x) be the solution of the differential equation cosec2 xdy + 2dx = (1 + y cos 2x) cosec2 xdx, with y(4π)=0. Then, the value of (y(0)+1)2is equal to:
(1)e1/2
(2)e−1/2
(3)e−1
(4)e
253.
A differential equation representing the family of parabolas with axis parallel to y-axis and whose length of latus rectum is the distance of the point (2,−3) form the line 3x+4y=5, is given by :
(1)10dx2d2y=11
(2)11dy2d2x=10
(3)10dy2d2x=11
(4)11dx2d2y=10
254.
Let y = y(x) be the solution of the differential equation xdy = (y + x3 cos x) dx with y(π) = 0, then y(2π) is equal to:
(1)4π2+2π
(2)2π2+4π
(3)2π2−4π
(4)4π2−2π
255.
Consider the family of all circles whose centers lie on the straight line y = x. If this family of circles is represented by the differential equation Py" + Qy' + 1 = 0, where P, Q are functions of x, y and y' (here y' = , y" = ), then which of the following statements is (are) true?
(1)P = y + x
(2)P = y – x
(3)P + Q = 1 – x + y + y' + (y')2
(4)P – Q = x + y – y' – (y')2
256.
Let y = y(x), y > 0, be a solution curve of the differential equation (1 + x2)dy = y(x - y)dx. If y(0)= 1 and y(22)=β then
(1)e3β−1=e(3+22)
(2)e3β−1=e(5+2)
(3)eβ−1=e−2(3+22)
(4)eβ−1=e−2(5+2)
257.
Let dxdy=bx+cy+aax−by+a, where a, b, c are constants, represent a circle passing through the point (2, 5). Then the shortest distance of the point (11,6) from this circle is :
(1)10
(2)8
(3)7
(4)5
258.
If the solution curve of the differential equation dxdy=x−yx+y−2passes through the point (2,1) and (k+ 1, 2), k>0, then
(1)2tan−1(k1)=loge(k2+1)
(2)tan−1(k1)=loge(k2+1)
(3)2tan−1(k+11)=loge(k2+2k+2)
(4)2tan−1(k1)=loge(k2k2+1)
259.
The differential equation of the family of circles passing through the points (0, 2) and (0, - 2) is
(1)2xydxdy+(x2−y2+4)=0
(2)2xydxdy+(x2+y2−4)=0
(3)2xydxdy+(y2−x2+4)=0
(4)2xydxdy−(x2−y2+4)=0
260.
Let us consider a curve, y = f(x) passing through the point (−2, 2) and the slope of the tangent to the curve at any point (x, f(x)) is given by f(x) + xf’(x) = x2.Then :
(1)x2 + 2xf(x) − 12 = 0
(2)x3 + xf(x) + 12 = 0
(3)x3 − 3xf(x) − 4 = 0
(4)x2 + 2xf(x) + 4 = 0
261.
Let y = y(x) be a solution curve of the differential equation, (1- x2y2)dx = ydx + xdy, If the line x = 1 intersects the curve y = y(x) at y = 2 and the line x = 2 intersects the curve y = y(x) at y = α, then a value of α is
(1)2(3e2+1)1−3e2
(2)2(3e2−1)1+3e2
(3)2(3e2−1)3e2
(4)2(3e2+1)3e2
262.
Let y = y1(x) and y = y2(x) be the solution curves the differential equation dxdy= y + 7 with initial conditions y1(0)= 0 and y2(0)= 1 respectively. Then the curves y = y1(x) and y = y2(x) intersect at
(1)no point
(2)two points
(3)one point
(4)infinite number of points
263.
Let y = y(x) be the solution of the differential equation (x − x3) dy = (y + yx2 − 3x4) dx, x > 2. If y(3) = 3, then y(4) is equal to:
(1)4
(2)12
(3)8
(4)16
264.
Let Ι be the purchase value of an equipment and V(t) be the value after it has been used for t years. The value V(t) depreciates at a rate given by differential equation dtdV(t) = – k(T – t), where k > 0 is a constant and T is the total life in years of the equipment. Then the scrap value V(T) of the equipment is :
(1)T2 – k1
(2)Ι – 2kT2
(3)Ι – 2k(T−t)2
(4)e–kT
265.
The slope of normal at any point (x, y), x > 0, y > 0 on the curve y = y(x) is given by xy−x2y2−1x2 ,If the curve passes through the point (1, 1), then e.y(e) is equal to
(1)1+tan(1)1−tan(1)
(2)tan(1)
(3)1
(4)1−tan(1)1+tan(1)
266.
Let y(x) be the solution of the differential equation 2x2dy + (ey − 2x) dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :
(1)0
(2)2
(3)loge2
(4)loge(2e)
267.
Suppose y = y(x) be the solution curve to the differential equation dxdy−y=2−e−xsuch that limx→∞y(x) is finite. If a and b are respectively the x- and y- intercepts of the tangent to the curve at x=0, then the value of a-4b is equal to_________.
268.
Let y=y(x) be the solution of the differential equation dy=eax+ydx;a∈N. If y(loge2)=loge2 and y(0)=loge(21), then the value of α is equal to -
269.
Let f : R → R be a differentiable function with f(0) = 0. If y = f(x) satisfies the differential equation dxdy = (2 + 5y)(5y – 2), then the value of limx→–∞f(x) is _______ .
270.
Let the solution curve y = y(x) of the differential equation (4 + x2)dy - 2x(x2 + 3y + 4)dx = 0 pass through the origin. Then y(2) is equal to________.