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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Indefinite Integration · Set 4 (Q91-120)
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91.
∑sin3(x)⋅cos3(x)dx=
(1)sin4(x)−sin6(x)+c
(2)cos4(x)−cos6(x)+c
(3)41sin4(x)−61sin6(x)+c
(4)41cos4(x)−61cos6(x)+c
92.
The value of x that satisfies the equation ∫2x|t|t2−1dt=12π is
(1)1
(2)0
(3)−2
(4)2
93.
If the integral ∫tanx−25tanxdx=x+aln|sinx−2cosx|+k, then a is equal to
(1)1
(2)2
(3)-1
(4)-2
94.
∫(x+1)(x+2)4(x+3)dx is equal to
(1)2(x+1)2+5(x+2)2+2(x+3)2+C
(2)7(x+2)7−5(x+2)5+C
(3)7(x+2)7+5(x+2)5+C
(4)7(x+3)7−5(x+3)5+C
95.
Let I(x)=∑(4x+6)(4x2+8x+3)3dx and I(0)=43+20. If I(21)=ba2+c, where a,b,c∈N,gcd(a,b)=1, then a+b+c is equal to
(1)30
(2)31
(3)29
(4)28
96.
If ∫(1+x3+x5)32x12+5x9dx=l(1+x3+x5)rxm+C then rm−l=
(1)3
(2)4
(3)5
(4)6
97.
The value of ∫1+x61+x4dx is
(1)tan−1x+31tan−1x3+C
(2)tan−1x−31tan−1x3+C
(3)tan−1x+31tan−1x2+C
(4)tan−1x+tan−1x3+C
98.
∫esinx⋅(secxsinx+1)dx is equal to
(1)sinx⋅esinx+c
(2)cosx⋅esinx+c
(3)esinx+c
(4)esinx(sinx+1)+c
99.
∫1+ex1dx is equal to
(1)loge(exex+1)+c
(2)loge(exex−1)+c
(3)loge(ex+1ex)+c
(4)loge(ex−1ex)+c
100.
If ∫sin−1(1+xx)dx=A(x)tan−1(x)+B(x)+C Where Cis a constant of integration,then the ordered pair (A(x),B(x)) can be
(1)(x+1,−x)
(2)(x+1,x)
(3)(x−1,−x)
(4)(x−1,x)
101.
If ∫(e2x+2ex−e−x−1)e(ex+e−x)dx=g(x)e(ex+e−x)+cwhere c is a constant of integration, then g(0)is equal to :
(1)e2
(2)1
(3)2
(4)e
102.
The value of ∫−2π2π1+excosxdx is
(1)0
(2)1
(3)-2
(4)2
103.
If (3−5x)(2+3x)1=3−5xA+2+3xB, then A:B is
(1)5:3
(2)2:3
(3)3:2
(4)3:5
104.
If ∑x2+4x+5x+5dx=alog(x2+4x+5)+btan−1(x+k)+C, then (a,b,k) equals
(1)(21,3,2)
(2)(21,1,2)
(3)(21,3,1)
(4)(1,3,2)
105.
If I=∫cos2xsinx+sin3xdx=Pcosx+Qlog(2cosx+12cosx−1)+c, (where c is a constant of integration), then the values of P and Q are respectively
(1)21,423
(2)21,42−3
(3)21,223
(4)21,22−3
106.
Let the equation of the curve passing through the point (0,1) be given by y=∫x3ex4dx. If the equation of the curve is written in the form x=f(y), then f(y)=
(1)log|4y−3|
(2)(log|4y−3|)1/4
(3)(log(43−4y))1/4
(4)log(44y−3)
107.
If In=∫04πtannxdx, where n is positive integer, then I10+I8 is equal to