In the print window choose “Save as PDF”. The file prints without a web address or date line.
Mere Teacher · Previous Year Questions
JEE Main Mathematics · Mathematical Logic & Miscellaneous Algebra · Set 6 (Q151-171)
Scan or visit mereteacher.com for free PYQ practice, timed CBT tests, step-by-step solutions and BroBot AI. Answers and solutions are free with a sign-up.
151.
The negation of the statement "All continuous functions are differentiable" is
(1)All continuous functions are not differentiable
(2)Some continuous functions are not differentiable
(3)Some continuous functions are differentiable
(4)All differentiable functions are continuous
152.
If x = 198 !, then value of the expression log2x1+log3x1+....+log198x1equals
(1)–1
(2)0
(3)1
(4)198
153.
Which of the following is NOT equivalent to p→q.
(1)p only if q
(2)q is necessary for p
(3)q only if p
(4)p is sufficient for q
154.
If log2, log(2x−1) and log(2x+3) are in A.P., then x is equal to
(1)5/2
(2)log25
(3)log23
(4)log32
155.
Which of the following quantified statement is true?
(1)The square of every real number is positive
(2)There exists a real number whose square is negative
(3)There exists a real number whose square is not positive
(4)Every real number is rational
156.
Which of the following statement is contingency?
(1)(p∨q)∨∼q
(2)(p∨q)∨∼p
(3)(p∨q)∧∼q
(4)p→(p∨q)
157.
The roots of the equation log2(x2 – 4x + 5) = (x – 2) are
(1)4, 5
(2)2, – 3
(3)2, 3
(4)3, 5
158.
If the statement p↔(q→p) is false, then true statement/statement pattern is
(1)p
(2)p→(p∨∼q)
(3)p∧(∼p∧q)
(4)(p∨∼q)→p
159.
If the truth value of the Boolean expression ((p ∨ q) ∧ (q → r) ∧ (∼ r)) → (p ∧q) is false then the truth values of the statements p,q,r respectively can be:
(1)TFT
(2)FFT
(3)TFF
(4)FTF
160.
The compound statement (P ∨ Q) ∧ (∼ P) ⇒ Q is equivalent to:
(1)P ∨ Q
(2)P∧∼ Q
(3)∼ (P ⇒ Q)
(4)∼ (P ⇒ Q) ⇔ P∧∼ Q
161.
If x satisfies |x – 1| + |x – 2| + |x – 3| ≥ 6, then
(1)0 ≤ x ≤ 4
(2)x ≤ –2 or x ≥ 4
(3)x ≤ 0 or x ≥ 4
(4)None of these
162.
Let ∗,□∈ {∧, ∨} be such that the Boolean expression (p∗∼ q) ⇒ (p□q) is a tautology. Then :
(1)∗ = ∨,□= ∨
(2)∗ = ∧,□ = ∧
(3)∗ = ∧,□ = ∨
(4)∗ = ∨,□ = ∧
163.
of the following is equivalent to the Boolean expression p∧∼ q?
(1)∼ (q → p)
(2)∼ p →∼ q
(3)∼ (p →∼ q)
(4)∼ (p → q)
164.
If logxa, ax/2 and logbx are in G.P. Then x is equal to
(1)loga (logba)
(2)loga(logea)+ loga logbb
(3)– loga(logab)
(4)none of these
165.
The number log27 is
(1)an integer
(2)a rational
(3)an irrational
(4)a prime number
166.
If logx 256 = 8/5, then x is equal to
(1)64
(2)16
(3)32
(4)8
167.
Which of the following is NOT true ?
(1){(p→q)∧(q→r)}→(p→r) is a tautology
(2)(p∧∼q)↔(p→q) is a tautology
(3)∼(p↔q)≡(p∧∼q)∨(∼p∧q)
(4)p→(q∧r)≡(p→q)∧(p→r)
168.
The number log27 is :
(1)an integer
(2)a rational number
(3)an irrational number
(4)a prime number
169.
Let f(x) = |x – 1|. Then
(1)f(x2) = (f(x))2
(2)f(x + y) = f(x) + f(y)
(3)f(|x|) = |f(x)|
(4)None of these
170.
The value of ((log29)2)log2(log29)1×(7)log471 is ___________
171.
The value of ((log29)2)log2(log29)1×(7)log471 is ___________.