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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Sequence & Series · Set 7 (Q181-210)
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181.
Consider two sets A and B, each containing three numbers in A.P. Let the sum and the product of the elements of A be 36 and p respectively and the sum and the product of the elements of B be 36 and q respectively. Let d and D be the common differences of AP’s in A and B respectively such that D=d+3,d>0. If p−qp+q=519, then p−q is equal to
(1)540
(2)450
(3)600
(4)630
182.
Let f:R→R be such that for all x∈R(21+x+21−x),f(x) and (3x+3−x) are in A.P., then the minimum value of f(x) is:
(1)1
(2)2
(3)3
(4)4
183.
If the sum of the second, third and fourth terms of a positive term G.P. is 3 and the sum of its sixth, seventh and.eighth terms is 243, then the sum of the first 50 terms of this G.P. is:
(1)132(350−1)
(2)131(350−1)
(3)261(349−1)
(4)261(350−1)
184.
The sum of the infinite series1+32+327+3312+3417+3522+… is equal to
(1)49
(2)415
(3)413
(4)411
185.
Let 2nd,8th and 44th, terms of a non-constant A.P. be respectively the 1st,2nd and 3rd terms of G.P. If the first term of A.P. is 1 then the sum of first 20 terms is equal to-
(1)980
(2)960
(3)990
(4)970
186.
Let 3,a,b,c be in A.P. and 3,a−1,b+1,c+9 be in G.P. Then, the arithmetic mean of a,b and c is :
(1)-4
(2)-1
(3)13
(4)11
187.
If the first term of an A.P. is 3 and the sum of its first four terms is equal to one-fifth of the sum of the next four terms, then the sum of the first 20 terms is equal to
(1)-1080
(2)-1020
(3)-1200
(4)-120
188.
If the sum of the series 1⋅(1+d)1+(1+d)(1+2d)1+…+(1+9d)(1+10d)1 is equal to 5 , then 50 d is equal to :
(1)10
(2)5
(3)15
(4)20
189.
The third term of a G.P. is 9. The product of its first five terms is
(1)35
(2)310
(3)39
(4)312
190.
Suppose that the number of terms in an A.P. is 2k,k∈N. If the sum of all odd terms of the A.P. is 40, the sum of all even terms is 55 and the last term of the A.P. exceeds the first term by 27 , then k is equal to:
(1)6
(2)5
(3)8
(4)4
191.
Let the first three terms 2,p and q, with q=2, of a G.P. be respectively the 7th,8th and 13th terms of an A.P. If the 5th term of the G.P. is the nth term of the A.P., then n is equal to:
(1)163
(2)151
(3)177
(4)169
192.
If 141+241+341+…∞=90π4, 141+341+541+…∞=α241+441+641+…∞=β then βα is equal to:
(1)23
(2)14
(3)18
(4)15
193.
The common difference of the A.P.: a1,a2,…,am is 13 more than the common difference of the A.P.: b1,b2,…,bn . If b31=−277,b43=−385 and a78=327, then a1 is equal to
(1)16
(2)21
(3)19
(4)24
194.
In an arithmetic progression, if S40=1030 and S12=57, then S30−S10 is equal to:
(1)525
(2)510
(3)515
(4)505
195.
The product of 241⋅4161⋅8481⋯∞=
(1)2
(2)2
(3)241
(4)1
196.
If each term of a geometric progression a1,a2,a3,… with a1=81 and a2=a1, is the arithmetic mean of the next two terms and Sn=a1+a2+…+an, then S20−S18 is equal to
(1)215
(2)−218
(3)218
(4)−215
197.
Assertion (A) : (1) +(1+2+4)+(4+6+9)+(9+12+16)+…+(81+90+100)=1000Reason (R) : ∑r=1n(r3−[r−1]3)=n3 for any natural number n
(1)Both (A) and (R) are true and (R) is the correct explanation of (A)
(2)Both (A) and (R) are true but (R) is not correct explanation of (A)
(3)(A) is true but (R) is false
(4)(A) is false but (R) is true
198.
For all n∈N, if 12+22+32+…+n2>x, then x=
(1)3n3
(2)2n3
(3)n3
(4)4n4
199.
3266+32510⋅1+32410⋅2+32310⋅22+…+310⋅224 is equal to:
(1)226
(2)325
(3)326
(4)225
200.
If a1,a2,a3....and b1,b2,b3.... are A.P. and a1 = 2, a10 = 3, a1b1 = 1 = a10b10 then a4b4 is equal to
(1)2735
(2)1
(3)2827
(4)2728
201.
A man saves Rs. 200 in each of the first three months of his service. In each of the subsequent months his saving increases by Rs. 40 more than the saving of immediately previous month. His total saving from the start of service will be Rs. 11040 after :
(1)18 months
(2)19 months
(3)20 months
(4)21 months
202.
Let x1, x2,..., x100 be in an arithmetic progression, with x1= 2 and their mean equal to 200. If yi=i(xi−i),1≤i≤100, then the mean of y1,y2,...,y10 is
(1)10100
(2)10101.50
(3)10049.50
(4)10051.50
203.
Let Sndenote the sum of first n-terms of an arithmetic progression. If S10 = 530, S5 = 140, then S20 − S6 is equal to :
(1)1862
(2)1842
(3)1852
(4)1872
204.
Let a, b, c and d be positive real numbers such that a + b + c + d= 11. If the maximum value of a5b3c2d is 3750β, then the value of β is
(1)90
(2)110
(3)55
(4)108
205.
If ∑r!(r3+6r2+2r+5)=α(11!)then the value ofαis equal to______
206.
If marithmetic means (A.Ms) and three geometric means (G.Ms) are inserted between 3 and 243 such that 4thA.M. is equal to 2ndG.M., then m is equal to
207.
Let α=12+42+82+132+192+262+…. upto 10 terms and β=∑n=110n4. If 4α−β=55k+40, then k is equal to
208.
Let A1,A2,A3,…… be squares such that for each n≥1, the length of the side of An equals the length of diagonal of An+1. If the length of A1is 12cm, then the smallest value of n for which area of Anis less than one, is
209.
The greatest integer less than or equal to the sum of first 100 terms of the sequence31,95,2719,8165,.... is equal to
210.
The sum of all the elements in the set {n ∈ {1, 2,…, , 100} H.C.F. of n and 2040 is 1} is equal to ____.