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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Sets, Relations & Functions · Set 21 (Q601-630)
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601.
Two newspapers A and B are published in a city. It is known that 25% of the city populations reads A and 20% reads B while 8% reads both A and B. Further, 30% of those who read A but not B look into advertisements and 40% of those who read B but not A also look into advertisements, while 50% of those who read both A and B look into advertisements. Then the percentage of the population who look into advertisement is:-
(1)13.9
(2)12.8
(3)13
(4)13.5
602.
Consider the following relations R : {(x, y)| x ,y are real numbers and x = wy for some rational number w} S = {(nm,qp) | m, n, p and q are integers such that n, q ≠ 0 and qm = pn} Then
(1)neither R nor S is an equivalence relation
(2)S is an equivalence relation but R is not an equivalence relation
(3)R and S both are equivalence relations
(4)R is an equivalence relation but S is not an equivalence relation
603.
If [x] denotes the greatest integer ≤x, then the domain of the function f(x)=[x]+24−x2 is
(1)(−∞,−2]∪[−1,2)
(2)(−∞,−2)∪[−1,2]
(3)(−∞,−2)∪(−1,2)
(4)(−∞,−1]∪[1,2]
604.
Let f:R→R be defined as f(x)=2x−1 and g:R−1→R be defined as g(x)=x−1x−21 . Then the composition function f(g(x)) is:
(1)both one-one and onto
(2)onto but not one-one
(3)neither one-one nor onto
(4)one-one but not onto
605.
The domain of the function, f(x)=log10(45x−x2) is
(1)[0,1]
(2)[1,4]
(3)[4,5]
(4)(−∞,∞)
606.
Let f(x) = {−1,x2−1,−2≤x<00≤x≤2 and g(x) = |f(x)| + f(|x|). Then, in the interval (–2, 2), g is :
(1)not differentiable at two point
(2)not continuous
(3)not differentiable at one point
(4)differentiable at all points
607.
If the domain of the function f(x)=log7(1−log4(x2−9x+18)) is (α,β)∪(γ,o), then α+β+γ+o is equal to
(1)17
(2)15
(3)16
(4)18
608.
If the function f:(−∞,−1]→(a,b] defined by f(x)=ex3−3x+1 is one-one and onto, then the distance of the point P(2b+4,a+2) from the line x+e−3y=4 is :
(1)21+e6
(2)41+e6
(3)31+e6
(4)1+e6
609.
The function f:R→R defined by f(x)=1+x2x is
(1)surjective but not injective
(2)bijective
(3)injective but not surjective
(4)neither injective nor surjective
610.
Let f:R→R be defined as f(x) = x-1 and g:R−1,1→R be defined as g(x)=x2−1x2 . Then the function fog is :
(1)one-one but not onto function
(2)onto but not one-one function
(3)both one-one and onto function
(4)neither one-one nor onto function
611.
Let a function f: N → N be defined by f(n)=⎩⎨⎧2n,n−1,2n+1,n=2,4,6,8...n=3,7,11,15....n=1,5,9,13,.... then f is
(1)one-one but not onto
(2)onto but not one-one
(3)neither one-one nor onto
(4)one-one and onto
612.
Let x denote the total number of one-one functions from a set A with 3 elements to a set B with 5 elementsand y denote the total number of one-one functions from the set A to the set A×B. Then:
(1)y=273x
(2)2y=91x
(3)y=91x
(4)2y=273x
613.
Let f(x)=2xn+λ, λ∈R, n∈N, and f(4)=133, f(5)=255. Then the sum of all the positive integer divisors of (f(3)−f(2)) is
(1)61
(2)60
(3)58
(4)59
614.
Let A={2,3,4} and B={8,9,12}. Then the number of elements in the relation R={((a1,b1),(a2,b2))∈(A×B,A×B):a1 divides b2 and a2 divides b1} is
(1)36
(2)24
(3)18
(4)12
615.
The relation R={(a,b):gcd(a,b)=1,2a=b,a,b∈Z} is
(1)Transitive but not reflexive
(2)Symmetric but not transitive
(3)Reflexive but not symmetric
(4)Neither symmetric nor transitive
616.
limx→12x2+x−3(2x−3)(x−1)=
(1)101
(2)−101
(3)52
(4)-
617.
The absolute minimum value, of the function f(x)=x2−x+1+[x2−x+1], where [t] denotes the greatest integer function, in the interval [−1,2] is
(1)43
(2)23
(3)41
(4)45
618.
Let R be the set of all real numbers. Let f:R→R be a function defined by f(x)={2x−5,if x<−3x+2,if −3≤x<53x+1,if x≥5 Match the following
List-I
List-II
(A) f(−5)+f(0)+f(−1)=
(I) 16
(B) f(f(5)+10f(−3))=
(II) 40
(C) f(∣f(−4)∣)=
(III) −32
(D) f(f(f(1)))=
(IV) −12
(V) 19
The correct answer is (A B C D)
(1)III II V I
(2)V IV I III
(3)IV V II I
(4)IV V III I
619.
Let f:R→R be defined by f(x)=1+x2x,x∈R. Then the range of f is:
(1)[−21,21]
(2)R−[−1,1]
(3)R−[−21,21]
(4)(−1,1)−{0}
620.
If the domain of the function f(x)=cos−1(42−∣x∣)+(loge(3−x))−1 is [−α,β)−{γ}, then α+β+γ is equal to :
(1)12
(2)9
(3)11
(4)8
621.
Let f:R→R be a function which satisfies f(x+y)=f(x)+f(y)∀x,y∈R. If f(1)=2. If f(1)=2 and g(n)=∑k=1n−1f(k),n∈N then thevalue of n, for which g(n)=20 is:
(1)20
(2)9
(3)4
(4)5
622.
The derivative of f(x)=xtan−1x with respect to g(x)=sec−1(2x2−11) is
(1)211−x2xtan−1x[1+x2logx+xtan−1x]
(2)−211−x˙2xtan−1[log(tan−1x)+x(1+x2)] ta
(3)1−x2−2xtan−1[1+x2logx+xtan−1x]
(4)−211−x2xtanx−1[1+x2logx+xtan−1x]
623.
If f(x)=⎩⎨⎧x−4∣x−4∣+a,a+b,x−4∣x−4∣+b,x<4x=4x>4 is continuous at x=4, then
(1)a=1,b=1
(2)a=1,b=−1
(3)a=0,b=0
(4)a=−1,b=1
624.
Consider the following lists. List I:(A)f(x)=x+2∣x+2∣,x=−2(B)g(x)=∣[x]∣,x∈R(C)h(x)=∣x−[x]∣,x∈R(D)f(x)=2−sin3x1,x∈RList II (ranges):1.(31,1)2.Z3.W4.[0,1)5.{−1,1} Match List I with List II.
(1)5 3 2 1
(2)3 2 4 1
(3)5 3 4 1
(4)1 2 3 4
625.
Let N be the set of natural numbers and two functions f and g be defined as f,g:N→N such that f(n)={2n+1,2n,if n is oddif n is even and g(n)=n−(−1)n. Then f∘g is:
(1)onto both not one-one
(2)one-one but not onto.
(3)both one-one and onto.
(4)neither one-one nor onto.
626.
The function f:X→Y defined by f(x)=sinx is one-one but not onto if X and Y are respectively equal to
(1)R and R
(2)[0,π] and [0,1]
(3)[0,2π] and [−1,1]
(4)[−2π,2π] and [−1,1]
627.
dxd(limy→2y−21(x1−x+y−21))=
(1)1/x2
(2)2/x3
(3)−2/x3
(4)1/x3
628.
If [x] denotes the greatest integer function, then the domain of the function f(x)=log(x2−x)x−[x], is
(1)(1,∞)
(2)(1,∞)−Z
(3)R−[21−5,21+5]
(4)[21−5,25+1]
629.
If dxd((x+1)2(x−2)2x+1)=(x−2)2A+(x+1)3B+(x+1)2C then A+B+C=
(1)3−2
(2)32
(3)31
(4)3−1
630.
Let f : R → R and g : R → R be respectively given by f(x) = |x| + 1 and g(x) = x2 + 1. Define h : R → R by h(x)={max{f(x),g(x)}min{f(x),g(x)}if x≤0,if x>0. The number of points at which h(x) is not differentiable is