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Mere Teacher · Previous Year Questions
JEE Main Mathematics · Statistics · Set 2 (Q31-60)
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31.
The mean of 5 observations is 4.4 and their variance is 8.24. If three of those observations are 1,2 and 6, then the other two observations are
(1)9,4
(2)9,5
(3)9,2
(4)9,13
32.
If both mean and variance of 50 observations x1,x2,….,x50 are equal to 16 and 256 respectively, then mean of (x1−5)2,(x2−5)2,…..,(x50−5)2 is
(1)357
(2)367
(3)377
(4)387
33.
The frequency distribution of the age of students in a class of 40 students is given below. Age 15 16 17 18 19 20 No of Students 5 8 5 12 x y If the mean deviation about the median is 1.25 , then 4x+5y is equal to :
(1)46
(2)43
(3)44
(4)47
34.
The variance of 50 observations is 7 . Suppose that each observation in this data is multiplied by 6 and then 5 is subtracted from it. Then the variance of that new data is
(1)37
(2)42
(3)247
(4)252
35.
The mean deviation about the mean for the following data is Class interval 0−10 10−20 20−30 30−40 40−50 50−60 60−70 Frequency 4 6 16 28 16 6 4
(1)35
(2)10
(3)15
(4)12
36.
If the mean of the data p,6,6,7,8,11,15,16, is 3 times p, then the mean deviation of the data from its mean is
(1)2.25
(2)3.75
(3)4.4
(4)2.5
37.
If the mean and variance of six observations 7,10,11,15,a,b are 10 and 320, respectively, then the value of |a-b|is equal to :
(1)9
(2)11
(3)7
(4)1
38.
If x is the mean of n observations x1,x2,…xn then the mean of the absolute deviations of these observations from x is
(1)the variance of the data
(2)the mean proportion of the data
(3)the standard deviation of the data
(4)the mean deviation of the data
39.
Let S be the set of all values of a1 for which the mean deviation about the mean of 100 consecutive positive integers a1,a2,a3,…,a100 is 25. Then Sis
(1)∅
(2)(99)
(3)N
(4)(9)
40.
Which of the following set of data has least standard deviation?
(1)10,20,30,40
(2)2,4,6,8
(3)3,6,9,12
(4)1,2,3,4
41.
If the mean of the discrete distribution 8,9,6,5,x,4,6, 5 is 6 , then its standard deviation (nearest to two decimal places) is
(1)2.50
(2)1.58
(3)0.51
(4)1.41
42.
Let M denote the median of the following frequency distribution. Class 0−4 4−8 8−12 12−16 16−20 Frequency 3 9 10 8 6 Then 20M is equal to :
(1)416
(2)104
(3)52
(4)208
43.
For the frequency distribution: Variate (x):x1x2x3…x15 Frequency (f):f1f2f3…f15 where0<x1<x2<x3<…x15=10 and ∑fi>0, the standard deviation cannot be :
(1)1
(2)6
(3)2
(4)4
44.
Let the mean and variance of the frequency distribution x : x1 = 2 x2 = 6 x3 = 8 x4 = 9 f : 4 4 α β be 6 and 6.8 respectively. If x3 is changed from 8to 7, then the mean for the new data will be:
(1)4
(2)5
(3)317
(4)316
45.
The mean and variance of a data of 10 observations are 10 and 2, respectively. If an observations α in this data is replaced by β, then the mean and variance become 10.1 and 1.99, respectively. Then α+β equals
(1)15
(2)5
(3)10
(4)20
46.
Students of two sections A and B of a class show the following results in a test conducted for 100 marks.
Section A Section B Number of students 50 60 Average marks in the test
45 45 Variance of distribution of marks
64 81 Then
(1)variability of section B> variability of section A
(2)variability of section A> variability of section B
(3)variability of section A= variability of section B
(4)The data is not sufficient to compare the variability of the sections
47.
If the mean and the variance of 6,4,a,8,b,12,10,13 are 9 and 9.25 respectively, then a+b+ab is equal to:
(1)103
(2)106
(3)100
(4)105
48.
Assertion (A): The variance of the first n odd natural numbers is 3n2−1.Reason (R): The sum of the first n odd natural numbers is n2 and the sum of the squares of the first n odd natural numbers is 3n(4n2−1).Which of the following alternatives is correct?
(1)(A) and (R) are true. (R) is correct explanation of (A)
(2)(A) and (R) are true, but (R) is not a correct explanation of (A)
(3)(A) is true, but (R) is false
(4)(A) is false, but (R) is true
49.
If the variance of the data 2,3,5,8,12 is σ2 and the mean deviation from the median for this data is M, then σ2−M=
(1)10.2
(2)5.8
(3)10.6
(4)8.2
50.
The number of values of a∈N such that the variance of 3,7,12,a,43−a is a natural number is:
(1)0
(2)2
(3)5
(4)infinite
51.
If the coeficient of variation and standard deviation are 60 and 21 respectively, the arithmetic mean of distribution is
(1)60
(2)30
(3)35
(4)21
52.
The mean and standard deviation of 20 observations are found to be 10 and 2 . respectively. On rechecking, it was found that an observation by mistake was taken 8 instead of 12 . The correct standard deviation is
(1)1.8
(2)1.94
(3)3.96
(4)3.86
53.
The variance of 20 observations is 5. If each one of the observations is multiplied by 2 , then the variance of the resulting observations is
(1)40
(2)80
(3)20
(4)10
54.
If the mean and variance of the frequency distribution xi 2 4 6 8 10 12 14 16 fi 4 4α15 8 β 4 5 are 9 and 15.08 respectively, then the value of α2+β2−αβ is_____.
55.
Consider a set of 3n numbers having variance 4 . In this set, the mean of first 2n numbers is6 and the mean ofthe remaining n numbers is 3 . A new set is constructed by adding 1 into each of first 2n numbers, andsubtracting 1 from each of the remaining n numbers. If the variance of the new set is k, then 9k is equal to____
56.
If the variance of the first n natural numbers is 10 and the variance of the first m even natural numbers is 16, then m+n is equal to …
57.
If the variance of 10 natural numbers 1,1,1,…,1,kis less than 10 , then the maximum possible value of k is
58.
Let X=(11,12,13,…,40,41) and Y=(61,62,63,…,90,91) be the two sets of observations. If xˉ and yˉ are their respective means and σ2 is the variance of all the observations in X∪Y, then xˉ+yˉ−σ2 is equal to _________
59.
Let X1,X2,……….X18 be eighteen observation such that ∑(Xi−α)=36 and ∑(Xi−β)2=90, where α and β are distinct real numbers. If the standard deviation of these observationsis 1, then the value of |α−β| is
60.
If the mean deviation about the mean of the numbers 1, 2, 3,....., n, where n is odd, isn5(n+1), then n is equal to_____