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Mere Teacher · Previous Year Questions
JEE Main Physics · Current Electricity · Set 12 (Q331-360)
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331.
Five identical resistors each of resistance R=1500Ω are connected to a 300V battery as shown in the circuit. The reading of the ideal ammeter A is
(1)51A
(2)53A
(3)52A
(4)54A
332.
A current of 3 amp. flows through the 2Ω resistor shown in the circuit. The power dissipated in the 5Ω resistor is
(1)1 watt
(2)5 watt
(3)4 watt
(4)2 watt
333.
The value of unknown resistance (x) for which the potential difference between B and D will be zero in the arrangement shown, is:
(1)3Ω
(2)42Ω
(3)9Ω
(4)6Ω
334.
What is the current through the battery in the circuit shown below
(1)1.5 A
(2)0.5 A
(3)0.25 A
(4)1.0 A
335.
The meter bridge shown in the balance position with QP=l2l1. If we now interchange the positions of galvanometer and cell, will the bridge work? If yes, what will be balanced condition? [NEET 2019]
(1)Yes, QP=l2+l1l2−l1
(2)No, no null point
(3)Yes, QP=l1l2
(4)Yes, QP=l2l1
336.
n identical resistance are taken in which 2n resistors are joined in series in the left gap and the remaining 2n resistances are joined in parallel in the right gap of a metre bridge. Balancing length in cm is.
(1)100⋅n2+4n2
(2)100⋅n2+1n2
(3)400⋅n2+41
(4)400⋅n2+11
337.
The resistances in the two arms of the meter bridge are 5 Ω and RΩ respectively When the resistance R is shunted with an equal resistance, the new balance point is at 1.6l1. The resistance R is
(1)10 Ω
(2)15 Ω
(3)20 Ω
(4)25 Ω
338.
A battery of 6V is connected to the circuit as shown below. The current I drawn from the battery is
(1)1A
(2)2A
(3)116 A
(4)34A
339.
A potentiometer wire has length 4 m and resistance 8 Ω. The resistance that must be connected in series with the wire and an accumulator of e.m.f. 2V, so as to get a potential gradient 1 mV per cm on the wire is
(1)44 Ω
(2)48 Ω
(3)32 Ω
(4)40 Ω
340.
In steady state, a capacitor of capacitance 2μF is charged to 4μC, as shown in figure. If the internal resistance of the cell is 0.5Ω, then the emf of the cell is
(1)4 V
(2)5 V
(3)2.5V
(4)2 V
341.
See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it?
(1)ε1– (i1 + i2)R – i1r1 = 0
(2)ε2– i2r2–ε1– i1r1 = 0
(3)– ε2– (i1 + i2)R + i2r2 = 0
(4)ε1– (i1 + i2)R + i1r1 = 0
342.
On interchanging the resistances, the balance point of a meter bridge shifts to the left by 10 cm. The resistance of their series combination is 1KΩ. How much was the resistance on the left slot before interchanging the resistances?
(1)550
(2)910
(3)990
(4)505
343.
Two bars of equal resistivity ρ and radii 'r' and '2r' are kept in contact as shown. An electric current I is passed through the bars. Which one of the following is correct
(1)Heat produced in bar (a) is 2 times the heat produced in bar (b)
(2)Electric field in both halves is equal
(3)Current density across AB is double that across BC.
(4)Potential difference across BC is 4 times that across AB.
344.
In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm. When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm. The ratio of the emf of two cells, ϵϵ1 is
(1)35
(2)58
(3)34
(4)23
345.
An ideal battery of 4 V and resistance R are connected in series in the primary circuit of a potentiometer of length 1m and resistance 5Ω. The value of R, to give a potential difference of 5mV across 10cm of potentiometer wire is:
(1)490Ω
(2)480Ω
(3)395Ω
(4)495Ω
346.
In the circuit shown the cells A and B have negligible resistances. For VA = 12V, R1 = 500Ω and R = 100Ω the galvanometer (G) shows no deflection. The value of VB is:
(1)4V
(2)2V
(3)12V
(4)6V
347.
The resistance in following circuit are R1=R2=R3=6.0Ω. The emf of the battery is 12V. When switch S is closed, the potential across resistance R1 is changed by an amount.
(1)−2V
(2)+2V
(3)−4V
(4)+4V
348.
The net resistance of the circuit between A and B is
(1)38Ω
(2)314Ω
(3)316Ω
(4)322Ω
349.
Two metal wires of identical dimension are connected in series. If σ1 and σ2 are the conductivities of the metal wires respectively, the effective conductivity of the combination is:
(1)2σ1σ2σ1+σ2
(2)σ1σ2σ1+σ2
(3)σ1+σ2σ1σ2
(4)σ1+σ22σ1σ2
350.
A wire of resistance R is bent into an equilateral triangle and an identical wire is bent into a square. The ratio of resistance between the two end points of an edge of the triangle to that of the square is Options
(1)8/9
(2)27/32
(3)32/27
(4)9/8
351.
In a meter bridge, the wire of length 1m has a non-uniform cross-section such that, the variation dldR of its resistance R with length I is dldR∝l1. Two equal resistances are connected as shown in the figure. The galvanometer has zero deflection when the jockey is at point P What is the length AP ?
(1)0.2m
(2)0.3m
(3)0.25m
(4)0.35m
352.
A wire of uniform resistance λΩ/m is bent into a circle of radius r and another piece of wire with length 2r is connected between points A and B(AOB) as shown in figure. The equivalent resistance between points A and B is ____Ω.
(1)83πλr
(2)3π+166πλr
(3)2πλr
(4)(π+1)2rλ
353.
Determine the charge on the capacitor in the following circuit:
(1)60μC
(2)2μC
(3)10μC
(4)200μC
354.
The meter bridge shown is in balance position with QP=l2l1. If we now interchange the positions of galvanometer and cell, will the bridge work?. If yes, what will be balanced condition?
(1)yes, QP=l2+l1l2−l1
(2)no, no null point
(3)yes, QP=l1l2
(4)yes, QP=l2l1
355.
In the circuit shown in the figure, if the potential at point A is taken to be zero, the potential at point B is
(1)+1V
(2)−1V
(3)+2V
(4)−2V
356.
In the given circuit the cells have zero internal resistance. The currents (in Amperes) passing through resistance R1 and R2 respectively, are:
(1)1,2
(2)2,2
(3)0.5,0
(4)0,1
357.
A wire of length 25 m and cross-sectional area 5mm2 having resistivity of 2×10−6Ωm is bent into a complete circle. The resistance between diametrically opposite points will be
(1)100Ω
(2)2.5Ω
(3)12.5Ω
(4)50Ω
358.
For the given circuit the current through battery of 6 V just after closing the switch 4S' will be .......... A.
359.
In the given figure, the value of V0 will be ____V.
360.
Two resistance of 100Ω and 200Ω are connected in series with a battery of 4V and negligible internal resistance. A voltmeter is used to measure voltage across 100Ω resistance, which gives reading as 1V. The resistance of voltmeter must be____ Ω.