Current Electricity PYQs Set 18 (PDF)

Set 18 of 25 · Questions 511-540 of 723

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Mere Teacher · Previous Year Questions JEE Main Physics · Current Electricity · Set 18 (Q511-540)
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511. $Equivalent resistance of the given circuit is$ (1) $R$ (2) $R/2$ (3) $R/4$ (4) $R/6$ 512. $A battery of 3.0 V is connected to a resistor dissipating 0.5 W of power. If the terminal voltage of the battery is 2.5 V, the power dissipated within the internal resistance is$ (1) $0.10 W$ (2) $0.072 W$ (3) $0.50 W$ (4) $0.125 W$ 513. $Consider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of the galvanometers R_{C} < R/2, which of the following statement(s) about any one of the galvanometers is(are) true?$ (1) $The maximum voltage range is obtained when all the components are connected in series$ (2) $The maximum voltage range is obtained when the two resistors and one galvanometer are connected in series, and the second galvanometer is connected in parallel to the first galvanometer$ (3) $The maximum current range is obtained when all the components are connected in parallel$ (4) $The maximum current range is obtained when the two galvanometers are connected in series, and the combination is connected in parallel with both the resistors.$ 514. $The power dissipated in the circuit shown in the figure is 30 watts. The value of R is$ (1) $20 Ω$ (2) $15 Ω$ (3) $10 Ω$ (4) $30 Ω$ 515. $The supply voltage to room is 120 V. The resistance of the lead wires is 6 Ω. A 60 W bulb is already switched on. What is the decrease of voltage across the bulb, when a 240 W heater is switched on in parallel to the bulb?$ (1) $zero Volt$ (2) $2.9 Volt$ (3) $13.3 Volt$ (4) $10.04 Volt$ 516. $In the circuit shown, the potential difference between A and B is$ (1) $1 V$ (2) $2 V$ (3) $3 V$ (4) $6 V$ 517. $In Wheatstone's network P = 2Ω, Q = 2Ω, R = 2Ω and S = 3Ω . The resistance with which S is to shunted in order that the bridge may be balanced is$ (1) $2Ω$ (2) $6Ω$ (3) $1Ω$ (4) $4Ω$ 518. $The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of 10 Ω is$ (1) $0.8 Ω$ (2) $1.0 Ω$ (3) $0.2 Ω$ (4) $0.5 Ω$ 519. $Two resistors of resistance, 100Ω and 200Ω are connected in parallel in an electrical circuit, The ratio of the thermal energy developed in 100Ω to that in 200Ω in a given time is [NEET 2022]$ (1) $2 : 1$ (2) $1 : 4$ (3) $4 : 1$ (4) $1 : 2$ 520. $Shown in the figure below is a meter-bridge set up with null deflection in the galvanometer. The value of the unknown resistor R is$ (1) $220$ (2) $110$ (3) $55$ (4) $13.75$ 521. $See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it?$ (1) $ϵ_{2} - i_{2} r_{2} - ϵ_{1} - i_{1} r_{1} = 0$ (2) $- ϵ_{2} - (i_{1} + i_{2}) R + i_{2} r_{2} = 0$ (3) $ϵ_{1} - (i_{1} + i_{2}) R + i_{1} r_{1} = 0$ (4) $ϵ_{1} - (i_{1} + i_{2}) R - i_{1} r_{1} = 0$ 522. $As shown in the figure, a network of resistors is connected to a battery of 24 V with an internal resistance of 3 Ω . The currents through the resistors R_{4} and R_{5} are I4 and I5 respectively. The values of I4 and I5 are;$ (1) $I_{4} = \frac{8}{5} and I_{5} = \frac{2}{5} A$ (2) $I_{4} = \frac{24}{5} A and I_{5} = \frac{6}{5} A$ (3) $I_{4} = \frac{6}{5} and I_{5} = \frac{24}{5} A$ (4) $I_{4} = \frac{2}{5} A and I_{5} = \frac{8}{5} A$ 523. $Two cells of emf E_{1} and E_{2} are joined in opposition (such that E_{1} > E_{2}). If r_{1} and r_{2} be the internal resistance and R be the external resistance, then the terminal potential difference is$ (1) $\frac{E _{1} + E _{2}}{r _{1} + r _{2} + R} \times R$ (2) $\frac{E _{1} - E _{2}}{r _{1} + r _{2} + R} \times R$ (3) $\frac{E _{1} + E _{2}}{r _{1} + r _{2}} \times R$ (4) $\frac{E _{1} - E _{2}}{r _{1} + r _{2}} \times R$ 524. $Two heating coils of resistances 10Ω and 20Ω are connected in parallel and connected to a battery of emf 12 V and internal resistance 1Ω . The power consumed by them are in the ratio$ (1) $1 : 4$ (2) $1 : 3$ (3) $2 : 1$ (4) $4 : 1$ 525. $Five equal resistances each of resistance R are connected as shown in the figure. A battery of V volts is connected between A and B . The current flowing in AFCEB will be$ (1) $\frac{3 V}{R}$ (2) $\frac{V}{R}$ (3) $\frac{V}{2 R}$ (4) $\frac{2 V}{R}$ 526. $Hive current carrying conductors meet at a point ' O' as shown in figure. The magnitude and direction of the current in conductor ' OP' is$ (1) $6.5 A from O to P$ (2) $9 A from P to O$ (3) $10.5 A from P to O$ (4) $11.5 A from O to P$ 527. $A wire of resistance R is bent into a triangular pyramid as shown in figure with each segment having same length. The resistance between points A and B is R / n . The value of n is:$ (1) $16$ (2) $10$ (3) $12$ (4) $14$ 528. $A galvanometer has a resistance of 50Ω and it allows maximum current of 5 mA . It can be converted into voltmeter to measure up to 100 V by connecting in series a resistor of resistance$ (1) $5975Ω$ (2) $20050Ω$ (3) $19950Ω$ (4) $19500Ω$ 529. $In the circuits shown below, the readings of voltmeters and the ammeters will be [NEET 2019]$ (1) $V_{1} = V_{2} and I_{1} > I_{2}$ (2) $V_{1} = V_{2} and I_{1} = I_{2}$ (3) $V_{2} > V_{1} and I_{1} > I_{2}$ (4) $V_{2} > V_{1} and I_{1} = I_{2}$ 530. $Two cells of emf 2E and E with internal resistance r_{1} and r_{2} respectively are connected in series to an external resistor R (see figure). The value of R, at which the potential difference across the terminals of the first cellbecomes zero is$ (1) $r_{1} + r_{2}$ (2) $\frac{r _{1}}{2} - r_{2}$ (3) $\frac{r _{1}}{2} + r_{2}$ (4) $r_{1} - r_{2}$ 531. $In the circuit, the value of the current, I is$ (1) $1 A$ (2) $0.5 A$ (3) $0.25 A$ (4) $0.75 A$ 532. $In the above circuit the current in each resistance is:$ (1) $0 A$ (2) $1 A$ (3) $0.25 A$ (4) $0.5 A$ 533. $The resistance of the meter bridge AB in given figure is 4Ω. With a cell of emf ε = 0.5 V and rheostat resistance R_{h} = 2Ω the null point is obtained at some point J. When the cell is replaced by another one of emf ε = ε_{2} the same null point J is found for R_{h} = 6 Ω. The emf ε_{2} is:$ (1) $0.5 V$ (2) $0.3 V$ (3) $0.4 V$ (4) $0.6 V$ 534. $From resistances of 100 ohm each are connected in the form of a square. The effective resistance along the diagonal points P R is:$ (1) $100$ (2) $180$ (3) $220$ (4) $440$ 535. $A, B and C are voltmeters of resistance R, 1.5 R and 3R respectively as shown in the figure. When some potential difference is applied between X and Y, the voltmeter readings are V_{A}, V_{B} and V_{C} respectively. Then,$ (1) $V_{A} = V_{B} = V_{C}$ (2) $V_{A} \neq = V_{B} = V_{C}$ (3) $V_{A} = V_{B} \neq = V_{C}$ (4) $V_{A} \neq = V_{B} \neq = V_{C}$ 536. $A cell of emf 1.8 V gives a current of 17 A when directly connected to an ammeter of resistance 0.06Ω . Internal resistance of the cell is$ (1) $0.046Ω$ (2) $0.066Ω$ (3) $0.10Ω$ (4) $10Ω$ 537. $A battery of unknown emf connected to a potentiometer has balancing length 560 cm . If a resistor of resistance 10Ω is connected in parallel with the cell the balancing length change by 60 cm . If the internal resistance of the cell is \frac{n}{10} Ω, the value of ’ n ’ is$ 538. $Two batteries of different emfs and different internal resistances are connected as shown. The voltage across AB in volts is$ 539. $When two identical batteries of internal resistance 1Ω each are connected in series across a resistor R, the rate of heat produced in R is J_{1} . When the same batteries are connected in parallel across R, the rate is J_{2} . If J_{1} = 2.25 J_{2} the value of R in Ω is:$ 540. $The ratio of the equivalent resistance of the network (shown in figure) between the points a and when switch is open and switch is closed is x : 8. The value of x is$