61.Find out the major product formed from the following reaction. (Me:−CH3)- (1)
- (2)
- (3)
- (4)
62.The product of an amine ' X ' with benzene sulphonyl chloride produces the product which is insoluble in alkali. The product of ' X ' with ethanoyl chloride is- (1)C6H5NHCOCH3
- (2)C6H5N(CH3)COCH3
- (3)C6H5N(CH3)CH2CH3
- (4)C6H5NHCH2CH3
63.An organic compound "A" on treatment withbenzene sulphonyl chloride gives compound B. B is soluble in dil.NaOH solution. Compound A is:- (1)C6H5−N−(CH3)2
- (2)C6H5−NHCH2CH3
- (3)C6H5−CH2NHCH3
- (4)C6H5−CH(CH3)−NH2
64.The correct order of the basic strength of methyl substituted amines in aqueous solution is [NEET 2019]- (1)(CH3)3N>CH3NH2>(CH3)2NH
- (2)(CH3)3N>(CH3)2NH>CH3NH2
- (3)CH3NH2>(CH3)2NH>(CH3)3N
- (4)(CH3)2NH>CH3NH2>(CH3)3N
65.Nitration of aniline in strong acidic medium also gives m-nitroaniline because [ NEET 2018]- (1)in absence of substituents nitro group always goes to m-position
- (2)in electrophilic substitution reactions amino group is m-directive
- (3)in-spite of substituents nitro group always goes to only m-position
- (4)in acidic (strong) medium aniline is present as anilinium ion
66.The major product of the following reaction is : (i)NaNO2/H+(ii)CrO3/H+(iii)H2SO4(conc.),∆- (1)
- (2)
- (3)
- (4)
67.Identify the compound that will react with Hinsberg's reagent to give a solid which dissolve in alkali. [NEET 2021]- (1)CH3−CH2−N¨(CH3)−CH2−CH3
- (2)CH3−CH2−N¨O2
- (3)CH3−CH2−N¨H−CH2
- (4)CH3−CH2−N¨H2
68.Which of the following is the most stable diazonium salt?- (1)C6H5CH2N2+X−
- (2)CH3N2+X−
- (3)CH3CH2N2+X−
- (4)C6H5N2+X−
69.The correct statement regarding the basicity of arylamines is [ NEET 2016,]- (1)Arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalised by interaction with the aromatic ring π-electron system.
- (2)Arylamines are generally more basic than alkylamines because of aryl group.
- (3)Arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridizwed
- (4)Arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalised by interaction with the aromatic ring π-electron system.
70.What will be the major product in the following mononitration reaction? HNO3conc.H2SO4- (1)
- (2)
- (3)
- (4)
71.When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is: (Given molar mass in gmol−1H:1,C:12,N:14,O:16,S:32)- (1)330
- (2)33
- (3)343
- (4)66
72.Choose the correct order of basicity of the following- (1)A > C > D > B
- (2)A > B > C > D
- (3)D > A > C > B
- (4)D > C > B > A
73.The final product [B] is:- (1)
- (2)
- (3)
- (4)
74.'A' and 'B' in the following reactions are: NaNO2/HClKCN(A)SnCl2/HCl/H3O+(B)- (1)
- (2)
- (3)
- (4)
75.Aniline dissolved in dilute HCl is reacted with sodium nitrate at 0° C. This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. HCl. The structure of the major product is :- (1)
- (2)
- (3)
- (4)
76.Isomeric amines with molecular formula C8HnN give the following tests Isomer(P) ⇒Can be prepared by Gabriel phthalimide synthesis Isomer(Q) ⇒ Reacts with Hinsberg's reagent to give solid insoluble in NaOH Isomer(R) ⇒Reacts with HONO followed by β-naphthol in NaOH to give red dye. Isomers(P), (Q) and (R) respectively are- (1)
- (2)
- (3)
- (4)
77.Products that are formed in the given reaction including by products are CH3CH2CH2CH2CONH2+Br2+4NaOH→- (1)CH3CH2CH2CH2CH2NH2+Na2CO3+2NaBr+2H2O
- (2)CH3CH2CH2CH2NH2+Na2CO3+2NaBr+2H2O
- (3)CH3CH2CH2CH2CH2NH2+2NaHCO3+Br2+2H2O
- (4)CH3CH2CH2CH2NH2+2Na2CO3+Br2+2H2O
78.A →(i)NaH(i)H3O+ B →(i)EOH(ii)H2SO4,ΔC 'A' shows positive Lassaign's test for N and its molar mass is 121 . 'B' gives effervescence with aq NaHCO3. 'C' gives fruity smell. Identify A,B and C from the following.- (1)
- (2)
- (3)
- (4)
79.Compound P is neutral, Q gives effervescence with NaHCO3 while R reacts with Hinsberg's reagent to give solid soluble in NaOH. Compound P is- (1)
- (2)
- (3)
- (4)
80.Which statement is NOT correct for p-toluenesulphonyl chloride?- (1)It is known as Hinsberg's reagent.
- (2)It is used to distinguish primary and secondary amines.
- (3)On treatment with secondary amine, it leads to a product, that is soluble in alkali.
- (4)It doesn't react with tertiary amines.
81.Which of the following ketone will NOT give enamine on treatment with secondary amines?[where t-Bu is -C(CH3)3]- (1)C2H5−C(=O)−C2H5
- (2)C2H5−C(=O)−CH3
- (3)t-Bu−C(=O)−t-Bu
- (4)
82.Given below are two statements: Statements-I : In Hofmann degradation reaction, the migration of only an alkyl group takes place from carbonyl carbon of the amide to the nitrogen atom. Statement-II : The group is migrated in Hofmann degradation reaction to electron deficient atom. choose the most appropriate answer from the options given below:- (1)Both Statement-I and Statement-II are correct
- (2)Both Statement-I and Statement-II are incorrect
- (3)Statement-I is correct but Statement-II is incorrect
- (4)Statement-I is incorrect but Statement-II is correct
83.The amine that reacts will Hinsberg's reagent to give an alkali insoluble product is [NEET 2019]- (1)CH3−CH(CH3)−NH−CH(CH3)−CH3
- (2)CH3−CH2−N(CH2CH3)−CH2CH3
- (3)CH3−C(NH2)(CH3)−CH2CH2CH3
- (4)CH3−C(CH3)2−CH(CH3)−NH2
84.Select the compound which on treatment with nitrous acid liberates nitrogen.- (1)Nitroethane
- (2)Triethylamine
- (3)Diethylamine
- (4)Ethylamine
85.Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be:- (1)3
- (2)5
- (3)6
- (4)1
86.How many of the transformation given below would result in aromatic amines?- (1)
- (2)
- (3)
- (4)
87.The starting material that produce pentanamine by Hoffmann bromamide reaction is- (1)CH3CH2CH2CH2CN
- (2)CH3CH2CH2CH2CONH2
- (3)CH3CH2CH2CH2NCO
- (4)CH3CH2CH2CH2CH2CONH2
88.What is the IUPAC name of (CH3)2NCH3 :- (1)Trimethylamine
- (2)2, 2-Dimethylmethanamine
- (3)N, N. Dimethylmethanamine
- (4)N-Methyldimethanamine
89.Match List I with List II List IA. Benzenesulphonyl chlorideB. Hoffmann bromamide reactionC. Carbylamine reactionD. Hoffmann orientationList III. Test for primary aminesII. Anti SaytzeffIII. Hinsberg reagentIV. Known reaction of Isocyanates. Choose the correct answer from the options given below:- (1)A-IV, B -III, C-II, D-I
- (2)A-IV, B -II, C-I, D-III
- (3)A-III, B -IV, C-I, D-II
- (4)A-IV, B -III, C-I, D-II
90.A hydrocarbon A(C4H8) on reaction with HCl gives a compound B(C4H9Cl) which on reaction with 1mol of NH3 gives compound C(C4H11N). On reacting with NaNO2 and HCl followed by treatment with water, compound C yields an optically active compound D. The compound D is- (1)
- (2)
- (3)
- (4)
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