Carboxylic Acids & Derivatives PYQs Set 5 (PDF)

Set 5 of 6 · Questions 121-150 of 177

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Mere Teacher · Previous Year Questions NEET Chemistry · Carboxylic Acids & Derivatives · Set 5 (Q121-150)
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121. $Benzoic acid gives benzene on being heated with X and phenol gives benzene on being heated with Y . Therefore, X and Y are respectively$ (1) $soda‐lime and copper$ (2) $Zn dust and NaOH$ (3) $Zn dust and soda‐lime$ (4) $soda‐lime and zinc dust.$ 122. $In a set of reactions m ‐bromobenzoic acid gave a product D . Identify the product D .$ (1) (2) (3) (4) 123. $The major product in the following reaction is :$ (1) (2) (3) (4) 124. $The major product ‘Y’ in the following reaction is: NaOCl X (i) SOC l_{2} (ii) aniline Y$ (1) (2) (3) (4) 125. $In the following sequence of reactions, CH_{3} CH = CHCH_{3} O_{3} A H_{2} O Zn B the alkene affords the compound 'B' The compound B is$ (1) $CH3COCH3$ (2) $CH3CH2COCH3$ (3) $CH3CHO$ (4) $CH3CH2CHO$ 126. $The correct match between Item-I (starting material) and Item- 11 (reagent) for the preparation of benzaldehvde is Item- I Item- II (I) Benzene (P) HCl and SnCl_{2}, H_{3} O^{+} (II) Benzonitrile (Q) H_{2}, Pd - BaSO_{4}, S and quinoline (III) Benzoyl Chloride (R) CO, HCl and AlCl_{3}$ (1) $(I) - (R), (II) - (P) and (III) - (Q)$ (2) $(I) - (P), (II) - (Q) and (III) - (R)$ (3) $(I) - (Q), (II) - (R) and (III)-(P)$ (4) $(I) - (R), (II) - (Q) and (III)-(P)$ 127. $The correct sequential addition of reagents in the preparation of m -nitrobenzoic acid from benzene is:$ (1) $B r_{2} / A l B r_{3}, H N O_{3} / H_{2} S O_{4},Mg/ ether, C O_{2}, H_{3} O^{+}$ (2) $B r_{2} / A l B r_{3},NaCN, H_{3} O^{+}, H N O_{3} / H_{2} S O_{4}$ (3) $B r_{2} / A l B r_{3}, H N O_{3} / H_{2} S O_{4},NaCN, H_{3} O^{+}$ (4) $H N O_{3} / H_{2} S O_{4}, B r_{2} / A l B r_{3},Mg/ ether, C O_{2}, H_{3} O^{+}$ 128. $Compound (X) undergoes following sequence of reactions to give the Lactone (Y).$ (1) $H - C (C H_{3})_{2} - C H O$ (2) $H O H_{2} C - C (C H_{3})_{2} - C H O$ (3) $H_{2} C (O H) - C H_{2} - C H_{2} - C H_{2} - C H O$ (4) $H_{2} C (C H_{3}) - C H_{2} - C H O$ 129. $Consider the above reaction and predict the major product.$ (1) (2) (3) (4) 130. $Which reactant will give the following alcohol on reaction with one mole of phenyl magnesium bromide (PhMgBr) followed by acidic hydrolysis ?$ (1) $CH - C \equiv N$ (2) $Ph - C \equiv N$ (3) $C H_{3} - C (= O) - O - P h$ (4) $P h - C (= O) - C H_{3}$ 131. $Maleic anhydride Maleic anhydride can be prepared by :$ (1) $Heating trans-but-2-enedioic acid$ (2) $Heating cis-but-2-enedioic acid$ (3) $Treating cis-but-2-enedioic acid with alcohol and acid$ (4) $Treating trans-but-2-enedioic acid with alcoholand acid$ 132. $Cyclohexylamine when treated with nitrous acid yields (P). On treating (P) with PCC results in (Q). When (Q) is heated with dil. NaOH we get (R) The final product (R) is :$ (1) (2) (3) (4) 133. $Acetone is treated with excess of ethanol in the presence of hydrochloric acid. The product obtained is :$ (1) $C H_{3} C H_{2} C H_{2} - C (= O) - C H_{3}$ (2) $C H_{3} C H_{2} C H_{2} - C (= O) - C H_{2} C H_{2} C H_{3}$ (3) $(C H_{3})_{2} C (O H) (O C_{2} H_{5})$ (4) $(C H_{3})_{2} C (O C_{2} H_{5})_{2}$ 134. $Identify the product (P) in the following reaction:$ (1) (2) (3) (4) 135. $The number of σ and π -bonds in 2 -formylbenzoic acid are respectively$ (1) $10,3$ (2) $14,3$ (3) $12,5$ (4) $17,5$ 136. $In this reaction : CH3CHO + HCN \to CH3CH (OH)CN H_{2} O CH3CH(OH)COOH an asymmetric centre is generated. The acid obtained would be :$ (1) $D-isomer$ (2) $L-isomer$ (3) $50% D + 50% L-isomer$ (4) $20% D + 80% L-isomer$ 137. $In a reaction, reagents 'X' and ' Y' respectively are :$ (1) $(C H_{3} C O)_{2} O/ H^{+} and C H_{3} OH/ H^{+}, ∆$ (2) $(C H_{3} C O)_{2} O/ H^{+} and (C H_{3} C O)_{2} O/ H^{+}$ (3) $C H_{3} OH/ H^{+}, ∆ and C H_{3} OH/ H^{+}, ∆$ (4) $C H_{3} OH/ H^{+} ∆ and (C H_{3} C O)_{2} O/ H^{+}$ 138. $In the above reaction, the reagent " A " is:$ (1) $NaBH_{4}, H_{3} O^{+}$ (2) $LiAlH_{4}$ (3) $Alkaline KMnO_{4}, H^{+}$ (4) $HCl, Zn - Hg$ 139. $Identify major product ' P' formed in the following reaction.$ (1) (2) (3) (4) 140. $Which one of the following product is formed when adipic acid is heated?$ (1) (2) (3) (4) 141. $The number of compound/s given below which contain/s - COOH group is :$ (1) $Sulphanilic acid$ (2) $Picric acid$ (3) $Aspirin$ (4) $Ascorbic acid$ 142. $Consider the reaction Identify A, X, Y and Z$ (1) $A-Methoxymethane, X-Ethanoic acid, Y-Acetate ion, Z-hydrazine.$ (2) $A-Methoxymethane, X-Ethanol, Y-Ethanoic acid, Z-Semicarbazide.$ (3) $A-Ethanal, X- Ethanol, Y-But-2-enal, Z-Semicarbazone.$ (4) $A-Ethanol, X-Acetaldehyde, Y-Butanone, Z-Hydrazone.$ 143. $The reagent, from the following, which converts benzoic acid to benzaldehyde in one step is$ (1) $L i A l H_{4}$ (2) $K M n O_{4}$ (3) $MnO$ (4) $N a B H_{4}$ 144. $In a set of the given reactions, acetic acid yielded a product Product C would be$ (1) $C H_{3} C H (O H) C_{2} H_{5}$ (2) $C H_{3} C O C_{6} H_{5}$ (3) $C H_{3} C H (O H) C_{6} H_{5} C_{2} H_{5}$ (4) $C H_{3} - C (C_{2} H_{5}) (O H) C_{6} H_{5}$ 145. $End product of the following reaction is : CH3CH2COOH$ (1) $C H_{3} C H (O H) C O O H$ (2) $C H_{2} (O H) C H_{2} C O O H$ (3) $CH2 = CHCOOH$ (4) $C H_{2} (C l) C H (O H) C O O H$ 146. $Decarboxylation of all six possible forms of diaminobenzoic acids C_{6} H_{3} (N H_{2})_{2} COOH yields three products A, B and C. Three acids give a product 'A', two acids gives a product 'B' and one acid give a product 'C'. The melting point of product 'C' is$ (1) $63°C$ (2) $90°C$ (3) $104°C$ (4) $142'C$ 147. $An unsaturated hydrocarbon X absorbs two hydrogen molecules on catalytic hydrogenation, and also gives following reaction : X O_{3} Zn/H_{2} O A [Ag (NH_{3})_{2}]^{+} B(3-oxo-hexanedicarboxylic acid) X will be :$ (1) (2) (3) (4) 148. $Compound 'A’ (molecular formula C_{3} H_{8} O) is treated with acidified potassium dichromate to form a product 'B' (mol. Formula C_{3} H_{6} O). 'B' forms a shining silver mirror on warming with ammonical A g N O_{3} . 'B' when treated with an aqueous solution of H_{2} N C O N H N H_{2}, HCl & sodium acetate gives a product 'C'. Identify the structure of 'C’$ (1) $C H_{3} C H_{2} CH = N N H C O N H_{2}$ (2) $C H_{3} - C (C H_{3}) = N - C O N H N H_{2}$ (3) $C H_{3} - CH = N.NH - C O N H_{2}$ (4) $C H_{3} C H_{2} CH = N C O N H N H_{2}$ 149. $Compound A (C_{9} H_{10} O) shows positive iodoform test. Oxidation of A with KMn O_{4} /KOH gives acid B (C_{8} H_{6} O_{4}) . Anhydride of B is used for the preparation of phenolphthalein. Compound A is:$ (1) (2) (3) (4) 150. $In the following reaction Aldehyde + Alcohol HCl Acetal Aldehyde Alcohol HCHO^{t} BuOH C H_{3} CHO MeOH The best combination is :$ (1) $HCHO and^{t} BuOH$ (2) $C H_{3} CHO and^{t} BuOH$ (3) $HCHO and MeOH$ (4) $C H_{3} CHO and MeOH$