91.Given: Co3++e−→Co2+;E0=+1.81V Pb4++2e−→Pb2+;Eo=+1.67V Ce4++e−→Ce3+;E∘=+1.61V Bi3++3e−→Bi;E∘=+0.20V oxidizing power of the species will increase in the order:- (1)Ce4+<Pb4+<Bi3+<Co3+
- (2)Bi3+<Ce4+<Pb4+<Co3+
- (3)Co3+<Ce4+<Bi3+<Pb4+
- (4)Co3+<Pb4+<Ce4+<Bi3+
92.The time required (in hours) to reduce 3mol of Fe3+ ions to Fe2+ ions with 2.0 amperes of current is (1F (=96500Cmol−1)- (1)30.2
- (2)40.2
- (3)10.2
- (4)15.2
93.The variation of λm of acetic acid with concentration is correctly represented as- (1)
- (2)
- (3)
- (4)
94.For the cell reaction 2Fe3+(aq)+2I−(aq)→2Fe2+(aq)+I2(aq) EcellΘ=0.24V at 298 K . The standard Gibbs energy (ΔrG⊖) of the cell reaction is [Given that Faraday constant F=96500Cmol−1 ]- (1)-46.32 kJ mol−1
- (2)-23.16 kJ mol−1
- (3)46.32kJmol−1
- (4)23.16kJmol−1
95.Calculate current in ampere required to deposit 4.8g Cu from its salt solution in 30 minutes. (Molar mass of Cu=63.5gmol−1 )- (1)8.1 ampere
- (2)6.4 ampere
- (3)10.5 ampere
- (4)12.3 ampere
96.The reduction potential of a half cell consisting of a Pt electrode immersed in 2.0MFe2+ and 0.02MFe3+ solution (in V) is Given (F2.303RT=0.059,EFe3+∣Fe2+0=0.771V)- (1)0.543
- (2)0.653
- (3)0.733
- (4)0.822
97.The reduction potential of hydrogen electrode at 25∘C in a neutral solution is (pH2=1) bar )- (1)0.059V
- (2)−0.059V
- (3)−0.413V
- (4)0.0V
98.Find the observed EMF of the cell Cd∣Cd2+(0.01M)∥ Cu2+(0.01M)∣Cu under conditions, internal resistance of 4Ω and producing a current of 0.15A. (Given, ECu2+/Cu∘=0.35V and E∘Cd2+/Cd=−0.4V )- (1)0.75V
- (2)0.15V
- (3)0.6V
- (4)0.9V
99.For hydrogen - oxygen fuel cell at one atm and 298KH2(g)+21O2(g)→H2O(l);ΔG∘=−240kJE∘ for the cell is approximately, (Given : F=96,500C )- (1)2.48V
- (2)1.24V
- (3)2.5V
- (4)1.26V
100.Given EFe+3/Fe+20=+0.76V and EI2/I−0=+0.55V. The equilibrium constant for the reaction taking place in galvanic cell consisting of above two electrodes is (F2.303RT=0.06)- (1)1×109
- (2)3×108
- (3)5×1012
- (4)1×107
101.38.6 amperes of current is passed for 100 seconds through an aqueous CuSO4 solution using platinum electrodes. The mass of copper consumed from the solution and volume of gas liberated at STP are respectively (molar mass of (Cu=63.54gmol−1).- (1)6.37g,0.448L
- (2)0.63g,0.224L
- (3)1.27g,0.224L
- (4)4g,0.448L
102.The product, which is not obtained during the electrolysis of brine solution is- (1)H2
- (2)HC1
- (3)NaOH
- (4)C12
103.What is the conductivity of 0.05MBaCl2 solution if its molar conductivity is 220Ω−1cm2mol−1 ?- (1)0.011Ω−1cm−1
- (2)0.033Ω−1cm−1
- (3)0.022Ω−1cm−1
- (4)0.044Ω−1cm−1
104.Calculate Ecello for Cd(s)(Cd++(1M)∥Ag+(1M))Ag(s) (ECdo=−0.403V;EAgo=0.799V)- (1)1.202V
- (2)−1.202V
- (3)0.396V
- (4)−0.396V
105.If hydrogen electrodes dipped in two solutions of pH=3 and pH=6 are connected by a salt bridge, the emf of the resulting cell is- (1)0.177V
- (2)0.3V
- (3)0.052V
- (4)0.104V
106.Which of the following cannot be considered as application of electrochemical series?- (1)Relative strength of reducing agent
- (2)Use of SHE in automobile battery
- (3)Relative strength of oxidising agent
- (4)Spontaneity of redox reaction
107.Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m–1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω. The molar conductivity of 0.5 M solution of the electrolyte in S m2 mol–1 is :- (1)5 × 10−4
- (2)5 × 10−3
- (3)5 × 103
- (4)5 × 102
108.For spontaneity of a cell, which is correct?- (1)ΔG=+ve,ΔE=+ve
- (2)ΔG=−ve
- (3)ΔG=0,ΔE=0
- (4)ΔG=−ve,ΔE=0
109.The reaction at cathode in the cells commonly used in clocks involves.- (1)reduction of Mn from +7 to +2
- (2)reduction of Mn from +4 to +3
- (3)oxidation of Mn from +3 to +4
- (4)oxidation of Mn from +2 to +7
110.Consider the following relations for emf of an electrochemical cell(i) EMF of cell=(Oxidation potential of anode) ‐(Reduction potential of cathode)(ii) EMF of cell=(Oxidation potential of anode) +( Reduction potential of cathode)(iii) EMF of cell = (Reductional potential of anode)+(Reduction potential of cathode) (iv) EMF of cell=(Oxidation potential of anode) ‐(Oxidation potential of cathode)Which of the above relations are correct?- (1)(iii) and (i)
- (2)(i) and (ii)
- (3)(iii) and (iv)
- (4)(ii) and (iv)
111.Salts of A (atomic weight 8 ), B (atomic weight 18 ) and C (atomic weight 50 ) were electrolysed under identical conditions using the same quantity of electricity. It was found that 2.4g of A was deposited, the weight of B and C deposited are 1.8g and 7.5g, respectively. The valences of A,B and C are, respectively,- (1)3,1 and 2
- (2)1,2 and 3
- (3)1,3 and 2
- (4)3,2 and 1
112.The molar conductivities ΛNaOAc0 and ΛHCl0 at infinite dilution in water at 25°C are 91.0 and 426.2 Scm2/mol respectively. To calculate ΛHOAc0, the additional value required is :- (1)ΛH2O0
- (2)ΛKCl0
- (3)ΛNaOH0
- (4)ΛNaCl0
113.Identify the gas produced due to reduction of NH4+ ions at cathode during working of dry cell.- (1)Ammonia
- (2)Hydrogen
- (3)Hydrogen chloride
- (4)Chlorine
114.The resistance of 0.1M weak acid HA in a conductivitycellis 2×103ohm. Thecellconstant of the cell is 0.78Cm−1 and λ6m of acid HA is 390Scm2mol−1. The pH of the solution is- (1)3.3
- (2)4.2
- (3)5
- (4)3
115.A solution of Ni(NO3)2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. How many mode of Ni will be deposited at the cathode?- (1)0.05
- (2)0.20
- (3)0.15
- (4)0.10
116.Which of the following does not conduct electricity?- (1)Fused NaCl
- (2)Solid NaCl
- (3)Brine solution
- (4)Copper
117.How can an electrochemical cell be converted into an electrolytic cell?- (1)Applying an external opposite potential lower than E0 cell.
- (2)Reversing the flow of ions in salt bridge.
- (3)Applying an external opposite potential greater than E0 cell-
- (4)Exchanging the electrodes at anode and cathode.
118.The amount of current in faraday, required for the reduction of 1mol of Cr2O72− ions to Cr3+ is- (1)1F
- (2)2F
- (3)6F
- (4)4F
119.For a cell given below: Ag(Ag+)(Cu2+)Cu Ag+−+e−→A+gE∘=x Cu2++2e−→,E∘=y E∘ cell is:- (1)x + 2y
- (2)2x + y
- (3)y –x
- (4)y – 2x
120.The molar conductivity of 0.027M methanoic acid is 40.42Scm2mol−1. The value of dissociation constant of this acid is (Given λH+∘=349.6Scm2mol−1 and λHCOO−∘=54.6S (cm2mol−1)- (1)1.5×10−5
- (2)6.0×10−5
- (3)4.5×10−4
- (4)3.0×10−4
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