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Set 17 of 22 · Questions 481-510 of 650

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NEET Chemistry · General Organic Chemistry · Set 17 (Q481-510)

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  1. 481.
    Which one of the following compounds will not be soluble in sodium bicarbonate ?
    1. (1)2,4,6-Trinitrophenol
    2. (2)Benzoic acid
    3. (3)o-Nitrophenol
    4. (4)Benzene sulphonic acid
  2. 482.
    The general molecular formula, which represents the homologous series of alkanol is
    1. (1)CnH2nO2
    2. (2)CnH2nO
    3. (3)CnH2n+1O
    4. (4)CnH2n+2O
  3. 483.
    The structure of isobutyl group in an organic compound is
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  4. 484.
    Which of the following is correct for stability of phenoxide ion?
    1. (1)Resonating structure of benzene ring
    2. (2)Localization of π-electrons in phenoxide ion
    3. (3)Delocalization of π-electrons in phenoxide ion
    4. (4)All of the above
  5. 485.
    The correct statement regarding electrophile is
    1. (1)electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from another electrophile
    2. (2)electrophiles are generally neutral species and can form a bond by accepting a pair of electrons from a nucleophile
    3. (3)electrophile can be either neutral or positively charged species and can form a bond by accepting a pair of electrons from a nucleophile
    4. (4)electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from a nucleophile.
  6. 486.
    Among the following the strongest acid is :
    1. (1)CH3COOH
    2. (2)C6H5COOH
    3. (3)m-CH3OC6H4COOH
    4. (4)p-CH3OC6H4COOH
  7. 487.
    The major product obtained in the photo catalyzed bromination of 2-methylbutane is :
    1. (1)1-bromo-2-methylbutane
    2. (2)1-bromo-3-methylbutane
    3. (3)2-bromo-3-methylbutane
    4. (4)2-bromo-2-methylbutane
  8. 488.
    Hyperconjugation involves overlap of the following orbitals
    1. (1)σ–σ
    2. (2)σ–p
    3. (3)p – p
    4. (4)π – π
  9. 489.
    Tertiary alkyl halides are practically inert to substitution by SN2 mechanism because of :
    1. (1)steric hindrance
    2. (2)inductive effect
    3. (3)instability
    4. (4)insolubility
  10. 490.
    In sodium fusion test of organic compounds, the nitrogen of the organic
    compound is converted into
    1. (1)sodamide
    2. (2)sodium cyanide
    3. (3)sodium nitrite
    4. (4)sodium nitrate.
  11. 491.
    The carboxyl functional group (– COOH) is present in
    1. (1)picric acid
    2. (2)barbituric acid
    3. (3)ascorbic acid
    4. (4)aspirin
  12. 492.
    In the hydroboration-oxidation reaction of propene with diborane, and NaOH, the organic compound formed is :
    1. (1)OH
    2. (2)
    3. (3)OH
    4. (4)COH
  13. 493.
    Among the following acid which has the lowest value ?
    1. (1)COOH
    2. (2)CH–COOH
    3. (3)HCOOH
    4. (4)COOH
  14. 494.
    The major product formed when 1,1,1-trichloro-propane is treated with aqueous potassium hydroxide is:
    1. (1)Propyne
    2. (2)1-Propanol
    3. (3)2-Propanol
    4. (4)Propionic acid
  15. 495.
    Pyridine is less basic than triethylamine because :
    1. (1)Pyridine has aromatic character
    2. (2)Nitrogen in pyridine is sp2 hybridised
    3. (3)Pyridine is a cyclic system
    4. (4)In pyridine, lone pair of nitrogen is delocalise
  16. 496.
    Lassaigne’s test is used in qualitative analysis to detect
    1. (1)nitrogen
    2. (2)sulphur
    3. (3)chlorine
    4. (4)all of these
  17. 497.
    In Dumas method, of an organic compound gave of nitrogen at STP. The percentage of nitrogen is
    1. (1)16.9
    2. (2)18.7
    3. (3)23.2
    4. (4)29.6
  18. 498.
    Cyclohexene _______is type of an organic compound.
    1. (1)Benzenoid aromatic
    2. (2)Benzenoid non-aromatic
    3. (3)Acyclic
    4. (4)Alicyclic
  19. 499.
    Which of the following molecules represents the order of hybridisation
    from left to right atoms?
    1. (1)—
    2. (2)—
    3. (3)—
    4. (4) — —
  20. 500.
    The IUPAC name of the compound shown below is
    1. (1)2 - Bromo-6-chlorocyclohex-1-ene
    2. (2)6-Bromo-2-chlorocyclohexene
    3. (3)3-Bromo-1-chlorocyclohexene
    4. (4)1-Bromo-3-chlorocyclohexene
  21. 501.
    Arrange the following labelled hydrogens in decreasing order of acidity
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  22. 502.
    What is the product when acetylene reacts with hypochlorous acid ?
    1. (1)COCl
    2. (2)CHO
    3. (3)CHCHO
    4. (4)COOH.
  23. 503.
    The heating of phenyl-methyl ethers with HI produces
    1. (1)ethyl chlorides
    2. (2)iodobenzene
    3. (3)phenol
    4. (4)benzene
  24. 504.
    In which of the following compounds, the C–Cl bond ionisation shall give most stable carbonium ion ?
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  25. 505.
    The IUPAC name of the following compound is:
    1. (1)4-Hydroxyhept-6-en-1-yne
    2. (2)Hept-1-en-6-yn-4-ol
    3. (3)Hept-6-en-1-yn-4-ol
    4. (4)4-Hydroxyhept-1-en-6-yne
  26. 506.
    Which of the following represent the given mode of hybridisation ––sp–sp from left to right.
    1. (1)H2C=CH–C≡N
    2. (2)HC≡C–C≡CH
    3. (3)C=C=C=
    4. (4)
  27. 507.
    Identify the compound that exhibits tautomerism.
    1. (1)2-Butene
    2. (2)Lactic acid
    3. (3)2-Pentanone
    4. (4)Phenol
  28. 508.
    The molecular formula of second homologue in the homologous series of mono carboxylic acids is
    1. (1)
    2. (2)
    3. (3)
    4. (4)
  29. 509.
    The IUPAC name of is
    1. (1)l‐bromo‐3‐methylbutane
    2. (2)2‐methyl‐3‐bromopropane
    3. (3)1‐bromopentane
    4. (4)2‐methyl ‐bromobutane.
  30. 510.
    In the following structure, the double bonds are marked as I, II, III and IV

    Geometrical isomerism is not possible at site (s) :
    1. (1)I
    2. (2)III
    3. (3)I and III
    4. (4)I and IV