241.How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 gHCl?- (1)0.011
- (2)0.029
- (3)0.044
- (4)0.333
242.A mixture of gases contains H2 and O2 gases in the ratio of 1: 4 (w/w) . What is the molar ratio of the two gases in the mixture?- (1)16:1
- (2)2:1
- (3)1:4
- (4)4:1
243.How many grams of Mg is required to completely reduce 100 ml, 0.1 M NO3− solution using the following reaction NO3−+Mg⟶Mg2++NH3- (1)0.96
- (2)0.62
- (3)0.24
- (4)0.75
244.What volume of oxygen gas (O) measured at 0oC and 1 atm, is needed to burn completely 1 L of propane gas (CH) measured under the same conditions?- (1)5L
- (2)10L
- (3)7L
- (4)6L
245.What volume of hydrogen gas at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron (atomic mass = 10.8) from the reduction of boron trichloride by hydrogen.- (1)44.8 lit.
- (2)22.4 lit.
- (3)89.6 lit.
- (4)67.2 lit.
246.In a reaction container, 100 g of hydrogen and 100 g of Cl2are mixed for the formation of HCl gas. What is the limiting reagent and how much HCl is formed in the reaction?- (1)H2 is limiting reagent and 36.5 g of HCl are formed.
- (2)Cl2is limiting reagent and 102.8g of HCl are formed.
- (3)H2is limiting reagent and 142 g of HCl are formed.
- (4)Cl2 is limiting reagent and 73 g of HCl are formed.
247.25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na+ and carbonate ions, CO32− are respectively (Molar mass of Na2CO3=106gmol−1)- (1)0.955 M and 1.910 M
- (2)1.910 M and 0.955 M
- (3)1.90 M and 1.910 M
- (4)0.477 M and 0.477 M
248.1.0 g of magnesium is burnt with 0.56 gO2 in a closed vessel. Which reactant is left in excess and how much? (At.wt.Mg=24,O=16)- (1)Mg, 0.16 g
- (2)O2,0.16g
- (3)Mg, 0.44 g
- (4)O2,0.28g
249.1 gram of a carbonate (M2CO3) on treatment with excess HCl produces 0.01186 mole of CO2. The molar mass of M2CO3 in g mol–1 is:- (1)84.3
- (2)118.6
- (3)11.86
- (4)1186
250.When a hydrocarbon A undergoes complete combustion it requires 11 equivalents of oxygen and produces 4 equivalents of water. What is the molecular formula of A ?- (1)C9H8
- (2)C11H4
- (3)C5H8
- (4)C11H8
251.At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires 375 mL air containing 20% O2 by volume for complete combustion. After combustion the gases occupy 330 mL. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is:- (1)C3H8
- (2)C4H8
- (3)C4H10
- (4)None
252.Oxidation numbers of A,B,C are +2,+5 and −2 respectively Possible formula of compound is- (1)A2(BC2)2
- (2)A3(BC4)2
- (3)A2(BC3)2
- (4)A3(B2C)2
253.C(s) + O2(g) →CO2(g) + 400 kJ C(s) + 21 O2(g) → CO(g) + 100 kJ When coal of purity 60% is allowed to burn in presence of insufficient oxygen, 60% of carbon is converted into 'CO' and the remaining is converted into ‘CO2’ The heat generated when 0.6 kg of coal is burnt is- (1)1600kJ
- (2)3200kJ
- (3)4400 kJ
- (4)6600 kJ
254.A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be- (1)1.4
- (2)3.0
- (3)2.8
- (4)4.4
255.A mixture of CaCl2 and NaCl weighing 4.44g is treated with sodium carbonate solution to precipitate all the Ca2+ ions as calcium carbonate. The calcium carbonate so obtained is heated strongly to get 0.56g of CaO. The percentage of NaCl in the mixture (atomic mass of Ca=40 ) is- (1)75
- (2)30.6
- (3)25
- (4)69.4
256.Among the following which one is not paramagnetic? [Atomic numbers; Be =4, Ne =10, As =33, Cl =17]- (1)Ne2+
- (2)Be+
- (3)Cl−
- (4)As+
257.Calculate the amount of CO2 gas produced, when 32 g of CH4 is burned with sufficient amount of oxygen. (Given, atomic weights of C = 12, O = 16, H = 1)- (1)132 g
- (2)44 g
- (3)88 g
- (4)176 g
258.If Avogadro number NA, is changed from 6.022×1023 mol−1 to 6.022×1020 mol−1 this would change- (1)the definition of mass in units of grams
- (2)the mass of one mole of carbon
- (3)the ratio of chemical species to each-other in a balanced equation
- (4)the ratio of elements to each-other in a compound
259.A mixture of 100 m mol of Ca(OH)2 and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL. The mass of calcium sulphate formed and the concentration of OH− in resulting the solution, respectively, are: (Molar mass of Ca(OH)2,Na2SO4 and CaSO4 are 74, 143 and 136 g mol−1, respectively; Ksp of Ca(OH)2is 5.5×10−6)- (1)1.9g,0.28molL−1
- (2)13.6g,0.28molL−1
- (3)1.9g,0.14molL−1
- (4)13.6g,0.14molL−1
260.For the given reaction: CaCO3+2HCl⟶CaCl2+H2O+CO2If 90gCaCO3 is added to 300 mL of HCl which contains 38.55%HCl by mass and has density 1.13gmL−1, then which of the following option is correct? Given molar mass of H,Cl,Ca and O are 1, 35.5, 40 and 16gmol−1 respectively.- (1)64.97 g of HCl remains unreacted
- (2)60.32 g of HCl remains unreacted
- (3)97.30 g of HCl reacted
- (4)32.85 g of CaCO3 remains unreacted
261.The unit J Pa−1is equivalent to- (1)m3
- (2)cm3
- (3)dm3
- (4)None of these
262.Candela is the SI unit of- (1)Luminous intensity
- (2)Luminous flux
- (3)Luminosity
- (4)Luminescence
263.A solution of two components containing n1 moles of the 1stcomponent and n2, moles of the 2nd component is preparedM1 and M2 are the molecular weights of component 1 and 2 respectively. If dis the density of the solution in gmL−1,C2 is the molarity and X2 is the mole fraction of the 2ndcomponent, then C2 can be expressed as- (1)C2=M1+x2(M2−M1)1000x2
- (2)C2=M1+x2(M2−M1)1000dx2
- (3)C2=M2+x2(M2−M1)dx2
- (4)C2=M2+x2(M2−M1)dx1
264.The significant figures in 3400 are- (1)2
- (2)5
- (3)6
- (4)4
265.A+2B⟶AB236.0 g of 'A' (Molar mass: 60gmol−1 ) and 56.0 g of ' B’ (Molar mass: 80gmol−1 ) are allowed to react. Which of the following statements are correct ?(A) ' A ' is the limiting reagent.(B) 77.0 g of AB2 is formed.(C) Molar mass of AB2 is 140gmol−1.(D) 15.0 g of A is left unreacted after the completion of reaction. Choose the correct answer from the options given below:- (1)(C) and (D) Only
- (2)(A) and (B) Only
- (3)(A) and (C) Only
- (4)(B) and (D) Only
266.Choose the correct statements. (A) Weight of a substance is the amount of matter present in it. (B) Mass is the force exerted by gravity on an object. (C) Volume is the amount of space occupied by a substance. (D)Temperatures below 0∘C are possible in Celsius scale, but in Kelvin scale negative temperature is not possible. (E) Precision refers to the closeness of various measurements for the same quantity. Choose the correct answer from the options given below :- (1)(A), (D) and (E) Only
- (2)(C), (D) and (E) Only
- (3)(A), (B) and (C) Only
- (4)(B), (C) and (D) Only
267.1 cc N2O at NTP contains- (1)2241.8×1022 atoms
- (2)224006.02×1023 molecules
- (3)2241.32×1023 electrons
- (4)All the above.
268.Which has maximum molecules?- (1)7 gN2
- (2)2 gH2
- (3)16 gNO2
- (4)16 gO2
269.How many seconds are there in 3 days?- (1)259200 s
- (2)172800 s
- (3)24800 s
- (4)72000 s
270.Mass of 0.1 mole of methane is- (1)1.6 g
- (2)0.1g
- (3)1g
- (4)16g
|