271.For the chemical reaction X ⇌ Y, the standard reaction Gibbs energy depends on temperature T (in K) as DrG°(in kJ mol–1) = 120 – 83T. The major component of the reaction mixture at T is:- (1)Y is T = 280 K
- (2)Y is T = 300 K
- (3)X if T = 315 K
- (4)X if T = 350 K
272.Equal volumes of monoatomic and diatomic gases at same initial temperature and pressure are mixed. The ratio of specific heats (Cp/Cv) of the mixture will be- (1)1
- (2)2
- (3)1.67
- (4)1.5
273.What is the change in entropy when 2.5 mole of water is heated from 270C to 870C? Assume that the heat capacity is constant. (Cp,m (H2O) = 4.2 J/g-K ln (1.2) = 0.18)- (1)16.6 J/K
- (2)9 J/K
- (3)34.02 J/K
- (4)1.89 J/K
274.A gas undergoes change from state A to state B. In this process, the heat absorbed and work done by the gas is 5 J and 8 J, respectively. Now gas is brought back to A by another process during, which 3 J of heat is evolved. In this reverse process of B to A :- (1)10 J of the work will be done by the surrounding on gas.
- (2)10 J of the work will be done by the gas.
- (3)6 J of the work will be done by the surrounding on gas.
- (4)6 J of the work will be done by the gas.
275.The heat of atomixation of methane and ethane are 360 kJ/mol and 620 kJ/mol, respectively. The longest wavelength of light capable of breaking the C-C bond is : (A vogadro number = 6.02 × 1023, h = 6.62 × 10–34 J s):- (1)2.48 × 103 nm
- (2)1.49 × 103 nm
- (3)2.49 × 104 nm
- (4)2.48 × 104 nm
276.The following graph indicates the system containing 1 mole of gas involving various steps. When it moves from z to x, the type of undergoing process is- (1)cyclic
- (2)isothermal
- (3)isochoric
- (4)isobaric
277.The standard entropies of CO2(g),C(s) and O2(g) are 213.5, 5.690 and 205 JK–1 respectively. The standard entropy of formation of CO2(g) is- (1)1.86 JK–1
- (2)1.96 JK–1
- (3)2.81 JK–1
- (4)2.86 JK–1
278.The enthalpy of hydrogenation of cyclohexene is −119.5kJmol−1. If resonance energy of benzene is −150.4kJmol−1, its enthalpy of hydrogenation would be- (1)−358.5kJmol−1
- (2)−508.9kJmol−1
- (3)−208.1kJmol−1
- (4)−269.9kJmol−1
279.Gibbs energy vs T plot for the formation of oxides is given below.
For the given diagram, the correct statement is-- (1)At 600°C, CO cannot reduce FeO
- (2)At 600°C, CO can reduce ZnO
- (3)At 600°C,C can reduce ZnO
- (4)At 600°C,C can reduce FeO
280.For which of the following processes, ΔS is negative ?- (1)C(diamond) → C(graphite)
- (2)N2(g, 1 atm) → N2(g, 5 atm)
- (3)N2(g, 273 K) → N2(g, 300 K)
- (4)H2(g) → 2H(g)
281.For a reaction,(4M(s)+nO2(g)→2M2On(s), the free energy change is plotted as a function of temperature. The temperature below which the oxide is stable could be inferred from the plot as the point at which- (1)the free energy change shows a change from negative to positive value
- (2)the slope changes from positive to negative
- (3)the slope changes from negative to positive
- (4)the slope changes from positive to zero
282.An ideal gas undergoes a cyclic process as shown in Figure. ΔUBC = –5 kJ mol–1, qAB = 2 kJ mol–1 WAB = –5 kJ mol–1, WCA = 3 kJ mol–1 Heat absorbed by the system during process CA is :- (1)– 5 kJ mol–1
- (2)+ 5 kJ mol–1
- (3)18 kJ mol–1
- (4)– 18 kJ mol–1
283.Ice and water are placed in a closed container at a pressure of 1 atm and temperature 273.15 K. If pressure of the system is increased 2 times, keeping temperature constant, then identify correct observation from following- (1)Volume of system increases .
- (2)The solid phase (ice) disappears completely.
- (3)Liquid phase disappears completely.
- (4)The amount of ice decreases.
284.If enthalpy of atomisation for Br2(I) is x kJ/mol and bond enthalpy for Br2 is y kJ/mol the relation between them :- (1)x> y
- (2)x < y
- (3)x = y
- (4)Relation does not exist
285.The hydration energies of K+and Cl−are −x and −ykJ/mol respectively. If the lattice energy of KCl is −zkJ/mol, then the heat of solution of KCl is:- (1)x+y+z
- (2)z−(x+y)
- (3)−z−(x+y)
- (4)x−y−z
286.For the equilibrium 2H2O ⇌ H3O+ + OH–, the value of DG° at 298 K is approximately :- (1)80 kJ mol–1
- (2)–100 kJ mol–1
- (3)–80 kJ mol–1
- (4)100 kJ mol–1
287.For an endothermic reaction, energy of activation is Ea and enthalpy of reaction is ΔH (both of these in kJ/mol). Minimum value of Ea will be- (1)less than ΔH
- (2)equal to ΔH
- (3)more than ΔH
- (4)equal to zero
288.Using the data provided, calculate the multiple bond energy (kJ mol–1) of a CºC bond C2H2. That energy is (take the bond energy of a C–H bond as 350 kJ mol–1) 2C(s) + H2(g) ¾® C2H2(g) DH = 225 kJ mol–1 2C(s) ¾® 2C (g) DH = 1410 kJ mol–1 H2(g) ¾® 2H(g) DH = 330 kJ mol–1- (1)1165
- (2)837
- (3)865
- (4)815
289.Match List-I with List-II List-I(A) Spontaneous process(B) Process with ΔP = 0,ΔT=0(C) ΔHreactlon(D) Exothermic processList-II(I) ΔH < 0(II) ΔGT.P < 0(III) Isothermal and isobaric process(IV) [Bond energies of molecules in reactants] [Bond energies of product molecules] Choose the correct answer from the options given below:- (1)(A) - (III), (B) - (II), (C) - (IV), (D) - (I)
- (2)(A) - (II), (B) - (III), (C) - (IV), (D) - (I)
- (3)(A) - (II), (B) - (III), (C) - (I), (D) - (IV)
- (4)(A) - (II), (B) - (I), (C) - (III), (D) - (IV)
290.(T=300KP=15bar1mole)(T=300KP=10bar1mole)(T=300KP=5bar1mole) Above shows a cyclic process. Calculate the total work done during one complete cycle..- (1)25/3L bar
- (2)−25/3L bar
- (3)50/3L bar
- (4)−50/3L bar
291.For a perfectly crystalline solid Cp,m=aT3+bT, where a and b are constants. If Cp,m is 0.40 J/Kmol at 10 K and 0.92 J/Kmol at 20 K, then molar entropy at 20 K is :- (1)0.92 J/Kmol
- (2)8.66 J/Kmol
- (3)0.813 J/Kmol
- (4)None of these
292.Given: (i) C(graphite)+O2(g)→CO2(g); ΔrH⊖=xkJmol−1 (ii) C(graphite)+21O2(g)→CO2(g); ΔrH⊖=ykJmol−1 (iii) CO(g)+21O2(g)→CO2(g); ΔrH⊖=zkJmol−1 Based on the above thermochemical equations, find out which one of the following algebraic relationship is correct?- (1)x = y – z
- (2)y = 2z – x
- (3)x = y + z
- (4)z = x + y
293.The effect of temperature on spontaneity of reactions are represented as:
ΔH ΔS Temperature Spontaneity (A) + ◻ any T Non spontaneous (B) + + low T spontaneous (C) - - low T Non spontaneous (D) - + any T spontaneous- (1)(B) and (C) only
- (2)(B) and (D) only
- (3)(A) and (D) only
- (4)(A) and (C) only
294.Formation of a solution from two components can be considered as (i) Pure solvent → separated solvent molecules, ΔH1 (ii) Pure solute →separated solute molecules,ΔH2 (iii) Separated solvent and solute molecules → solution, ΔH3 Solution so formed will be ideal if- (1)ΔHsoln=ΔH1+ΔH2+ΔH3
- (2)ΔHsoln=ΔH1+ΔH2−ΔH3
- (3)ΔHsoln=ΔH1−ΔH2−ΔH3
- (4)ΔHsoln=ΔH3−ΔH1−ΔH2
295.For the reaction, A(g)+B(g)→C(g)+D(g), ΔH∘ and ΔS∘ are, respectively, −29.8 kJmol−1 and −0.100 kJK−1mol−1 at 298 K. The equilibrium constant for the reaction at 298 K is:- (1)1
- (2)10
- (3)1.0 × 10–10
- (4)1.0 × 1010
296.The incorrect expression among the following is:- (1)ΔStotalΔGsystem=−T
- (2)In isothermal process, wreversible=−nRTℓnViVf
- (3)lnK=RTΔH0−TΔS0
- (4)K=e−ΔG0/RT
297.Find the heat required to make water of 30∘C from 10 g of ice at 0.0∘C. (Enthalpy of fusion of ice =333.55 Jg−1, CP of water =4.18 Jg−1K−1)- (1)4.0kJ
- (2)5.0kJ
- (3)3.59kJ
- (4)4.59kJ
298.Match the LIST-I with LIST-II List-I (Thermodynamic Process)( A) Work done in reversible, isothermal expansion of 2 mol ideal gas from 2dm3 to 20dm3 at 300 K(B) Work done in irreversible isothermal expansion of 1 mol ideal gas from 1m3 to 3m3 at 300 K against constant pressure 3 kPa(C) Change in internal energy for adiabatic expansion of 1 mol ideal gas, ΔT=320K , CV=23R(D) Change in enthalpy at constant pressure of 1 mol ideal gas, ΔT=337K , Cp=25RList-II (Magnitude in kJ)(I) 4(II) 11.5(III) 6(IV) 7 Choose the correct answer from the options given below:- (1)A-II, B-III, C-I, D-IV
- (2)A-III, B-II, C-IV, D-I
- (3)A-II, B-I, C-III, D-IV
- (4)A-I, B-II, C-III, D-IV
299.Given below are two statements: Statement I: When a system containing ice in equilibrium with water (liquid) is heated, heat is absorbed by the system and there is no change in the temperature of the system until whole ice gets melted. Statement II: At melting point of ice, there is absorption of heat in order to overcome intermolecular forces of attraction within the molecules of water in ice and kinetic energy of molecules is not increased at melting point. In the light of the above statements, choose the correct answer from the options given below- (1)Both Statement I and Statement II are false
- (2)Statement I is true but Statement II is false
- (3)Both Statement I and Statement II are true
- (4)Statement I is false but Statement II is true
300.Calculate ΔrH(kJmol−1) of the following reaction C2H5OH(I)+7/2O2(g)→2CO2(g)+3H2O(I) Molecule ΔfH0(kJmol−1) C2H5OH(I) -280 CO2(g) -400 H2O(l) -290- (1)-1950
- (2)-1100
- (3)-1390
- (4)-700
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