In the Claisen-Schmidt reaction to prepare 351 g of dibenzalacetone using 87 g of acetone, the amount of benzaldehyde required is _____g. (Nearest integer)

Question

Accepted Answer

Correct answer: 318. (318) mw of benzaldehyde =106 106 3=318 gm. Benzaldehyde is required to give 1.5 mole (or 351 gm ) product

$In the Claisen-Schmidt reaction to prepare 351 g of dibenzalacetone using 87 g of acetone, the amount of benzaldehyde required is _____g. (Nearest integer)$

Solution

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