2.5 g of protein containing only glycine (C_2H_5NO_2) is dissolved in water to make 500 mL of solution. The osmotic pressure of this solution at 300 K is found to be 5.03 x 10^-3 bar. The total numbe…

Question

2.5 g of protein containing only glycine (C_2H_5NO_2) is dissolved in water to make 500 mL of solution. The osmotic pressure of this solution at 300 K is found to be 5.03 x 10^-3 bar. The total number of glycine units present in the protein is____ (Given : R = 0.083 L bar K^-1 mol^-1)

Accepted Answer

Correct answer: 330. (330) π = CRT 5.03 x10^-3= Cx0.083x300 C = 0.202 x10^-3M Moles of protein = 0.202 x 10^-3 x 0.5 = 10^-4x1.01 1.01x10^-4= 2.5M M(molar mass of protein) = 24752 ∴No. of glycine units = 2 4 7 5 27 5 = 330.03

Solution

More Biomolecules PYQs