If 75 \% of a first order reaction was completed in 90 minutes, 60 \% of the same reaction would be completed in approximately (in minutes) (Take : log ⁡2=0.30 ; log ⁡2.5=0.40)

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Accepted Answer

Correct answer: 60. 60 Time for completion of 75 \% order reaction =90 min. ∴ Half life t_ 12= 12 t_ 34 = 902=45 min Rate constant, K= 0.69345 min^-1 Time for completion of 60 \% of the reaction, t_60 \%= 2.303K log ⁡ 104 = 2.303 450.693 [1-0.6 ] ≃60

$If 75 % of a first order reaction was completed in 90 minutes, 60 % of the same reaction would be completed in approximately (in minutes) (Take : log 2 = 0.30; log 2.5 = 0.40)$

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