JEE Previous Year Question

The standard reduction potentials at 295 K for the following half cells are given below:
+ + 3e- NO(g)+2H2O E° = 0.97 V
(aq)+ V(s) E° = -1.19 V
(aq)+3e- Fe(s) E° = -0. 04 V
(aq)+e- Ag(s) E° = 0.80 V
(aq)+3e- Au(s) E° = 1. 40 V
The number of metal(s) which will be oxidised by in aqueous solution is_____.

Topic: JEE PYQ

Answer: 3. Full step-by-step solution below.

Correct answer: 3

Solution

(3) For feasibility, check, E° = E°- E° > 0
The E° values when metal acts as anode and reaction is cathodic reaction.
For Vanadium metal, E° = 0.97 + 1.19 = 2.16V
For Iron metal, E° = 0. 97 + 0. 04 = 1. 01V
For silver metal, E° = 0.97 - 0.80 = 0.17V
For Gold metal, E° = 0.97 - 1.140 = -0.17V
For electrodes having oxidation potential greater than -0.97 V, E° > 0
Ag, Fe and V can be oxidised

More Electrochemistry PYQs