An analyst wants to convert 1 L HC1 of pH = 1 to a solution of HC1 of pH = 2. The volume of water needed to do this dilution is_____mL. (Nearest integer)

Question

Accepted Answer

Correct answer: 9000. (9000) The concentration of H^+ or say HC1 in both the given solution is 10^-1 and 10^-2 mole L^-1 respectively. For the given amount of HC1 the concentration depends over dilution hence M_1V_1 = M_2V_2 M_1M_2= V_2V_1 1 0^−11 0^−2= V_21 L V_2 = 10 L = 10000 mL ∆V = 10000-1000 mL = 9000 mL

$An analyst wants to convert 1 L HC1 of pH = 1 to a solution of HC1 of pH = 2. The volume of water needed to do this dilution is_____mL. (Nearest integer)$

Solution

More Ionic Equilibrium PYQs