A 20.0 mL solution containing 0.2g impure H_2O_2 reacts completely with 0.316g of KMnO_4 in acid solution. The purity of H_2O_2 (in \%) is (mol. wt. of H_2O_2=34 mol. wt. of KMnO_4=158 )

Question

Accepted Answer

Correct answer: 85. 85 5H_2O_2+2 MnO_4^-+6H^+ 2 Mn^2++5O_2+8H_2O Moles of KMnO_4= 0.316158=2 10^-3 Equivalents of H_2O_2=Equivalent of KMnO_4 =2 10^-3 5=0.01 Moles of H_2O_2= 0.012=0.005 Mass of pure H_2O_2=0.005 34=0.170 gm Percentage purity = 0.170.2 100=85 \%

$A 20.0 mL solution containing 0.2 g impure H_{2} O_{2} reacts completely with 0.316 g of KMnO_{4} in acid solution. The purity of H_{2} O_{2} (in %) is (mol. wt. of H_{2} O_{2} = 34 mol. wt. of KMnO_{4} = 158)$

Solution

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