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JEE Previous Year Question

$Highly pure dilute solution of sodium in liquid ammonia :$

Topic: JEE PYQ

Answer: A, B. Full step-by-step solution below.

A $shows blue colour.$
B $exhibits electrical conductivity.$
C $produces sodium amide.$
D $produces hydrogen gas$

Correct answer: A, B

Solution

(a,b) M + (x + y) N H_{3} \to [M (N H_{3})_{x}]^{+} + [e(N H_{3})_{y}]^{-} The electrical conductivity is due to the solvated ions and blue colour is due to solvated electrons.

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