A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is__________x $1 0^{21}$ (Nearest integer)
(Given $N_{A}$ = 6.02 $x 1 0^{23}$ )

Question

A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is__________x 10^21 (Nearest integer) (Given N_A = 6.02 x10^23)

Accepted Answer

Correct answer: 36. (36) One unit cell of hep contains = 18 voids No, of voids in 0.02 mol of hcp = 1 86 x 6.02 x10^23x 0.02 ≈ 3.6 x10^22 ≈ 36 x10^21

$A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is__________x 1 0^{21} (Nearest integer) (Given N_{A} = 6.02 x 1 0^{23})$

Solution

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