2.0 g of H_2 gas is adsorbed on 2.5 g of platinum powder at 300 K and 1 bar pressure. The volume of the gas adsorbed per gram of the adsorbent is ________mL.(Given : R = 0.083 L bar K^-1 mol^-1)

Question

Accepted Answer

Correct answer: 9960. (9960) Volume of H_2 = n R Tp= 22× 0.0 8 3×3 0 01 = 24.92 = 24900 mL So 'g platinum adsorb = 2 4 9 0 02.5mLH_2 = 9960

$2.0 g of H_{2} gas is adsorbed on 2.5 g of platinum powder at 300 K and 1 bar pressure. The volume of the gas adsorbed per gram of the adsorbent is ________mL.(Given : R = 0.083 L bar K^{- 1} m o l^{- 1})$

Solution

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