If the tangent drawn at a point P on the curve y=3x^2-5x+7 is parallel to its chord joining the points (1 ,y_1 ) and (2 ,y_2 ) on it, then the x-coordinates of the point P is

Question

Accepted Answer

Correct answer: B. (b) The given curve is y=3x^2-5x+7 Let the point P (h ,k ). Hence, k=3h^2-5h+7......(i) Now, slope at P is ( dy dx )_P=6h-5= y_2-y_12-1 ∵y_1=3-5+7=5 and y_2=12-10+7=9 ( ∴ dy dx )_P=6h-5= 9-51 ⇒6h-5=4 ⇒6h=9 ⇒h= 32 So, x-coordinate of point P is 32.

$If the tangent drawn at a point P on the curve y = 3 x^{2} - 5 x + 7 is parallel to its chord joining the points (1, y_{1}) and (2, y_{2}) on it, then the x -coordinates of the point P is$

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