The area (in sq. units) of the region bounded by the curve x^2=4y and the straight line x=4y-2 is :

Question

Accepted Answer

Correct answer: B. (b) Let points of intersection of the curve and the line be P and Q x^2=4 ( x+24 )x^2-x-2=0x=2 ,-1 Point are (2 ,1 ) and (-1 , 14) Area= 0.05em 0.05em( ( x+24 )- ( x^24 )) dx=( x^28+ 12x- x^312)_-1^2 =( 12+1- 23)-( 18- 12+ 112)= 98

$The area (in sq. units) of the region bounded by the curve x^{2} = 4 y and the straight line x = 4 y - 2 is :$

Solution

More Area Under Curves PYQs