The area enclosed by the closed curve C given by the differential equation dy dx+ x-1y-2=0, y (1 )=0 is 4 . Let P and Q be the points of intersection of the curve C and the y-axis. If normals at P an…

Question

The area enclosed by the closed curve C given by the differential equation dy dx+ x-1y-2=0, y (1 )=0 is 4 . Let P and Q be the points of intersection of the curve C and the y-axis. If normals at P and Q on the curve C intersect x-axis at points R and S respectively, then the length of the line segment RS is

Accepted Answer

Correct answer: D. (d) dy dx+ x+ay-2=0 dy dx= x+a2-y a+c=- 12 asy (1 )=0 x^2+y^2=2 ax-4y-1-2a=0 r^2=4 r^2=4 4= a^2+4+1+2a (a+1)^2=0 P ,Q=(0 ,2 3) Equation of normal P, Q are y-2= 3 (x-1 ) y-2=- 3 (x-1 ) R=(1- 2 3 ,0) S=(1+ 2 3 .0) RS= 4 3=4 33

Solution

More Area Under Curves PYQs