Let the area of the region \(x,y): |2x-1| y |x^2-x|,\ 0 x 1\ be A. Then (6A+11)^2 is equal to ________

Question

Accepted Answer

Correct answer: 125. (125) y (2x-1) ,y (x^2-x) Both curve are symmetric about x= 12 Hence A=2 (-x^2+3x-1) dx=2( -x^23+ 32x^2-x)_ 3- 52^ 12 Onsolving 6A+11= 5 5

$Let the area of the region {(x, y) : ∣2 x - 1∣ \leq y \leq ∣ x^{2} - x ∣, 0 \leq x \leq 1} be A . Then (6 A + 11)^{2} is equal to ________$

Solution

More Area Under Curves PYQs