Choose the correct statement about two circles whose equations are given below:
$x^{2} + y^{2} - 10 x - 10 y + 41 = 0$
$x^{2} + y^{2} - 22 x - 10 y + 137 = 0$

Question

Choose the correct statement about two circles whose equations are given below: x^2+y^2-10x-10y+41=0 x^2+y^2-22x-10y+137=0

Accepted Answer

Correct answer: C. c JEE Main 2021 x^2+y^2-10x-10y+41=0 A (5 ,5 ) ,R_1=3 x^2+y^2-22x-10y+137=0 B (11 ,5 ) ,R_2=3 AB=6=R_1+R_2 Touch each other externally ⇒circles have only one meeting point.

$Choose the correct statement about two circles whose equations are given below: x^{2} + y^{2} - 10 x - 10 y + 41 = 0 x^{2} + y^{2} - 22 x - 10 y + 137 = 0$

Solution

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