The equation of tangents to the circle x^2+y^2=4 which are parallel to x+2y+3=0 are

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Correct answer: D. (d) : Given, equation of the circle is x^2+y^2=4 and equation of the line is x+2y+3=0 Slope of the line =-1/2 Since, the required tangents are parallel to the given line. ∴ Slope of tangents (m )=- 12 We know that the equation of the tangents to the circle x^2+y^2=a^2 with slope m are y= mx a^2(1+m^2) ∴ The required equation of tangents are y =- 12x (2 )^2(1+ ( -12 )^2) ⇒y =- 12x 5 ⇒2y+x= 2 5

$The equation of tangents to the circle x^{2} + y^{2} = 4 which are parallel to x + 2 y + 3 = 0 are$

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