Let z_0 be a root of a quadratic equation, x^2+x+1=0. If z=3+6iz_0^81-3iz_0^93, then arg z is equal to:

Question

Accepted Answer

Correct answer: A. (a) JEE Main 2019 ∵ z_0 is a root of quadratic equation x^2+x+1=0 ∴z_0= or ^2 ⇒z_0^3=1 ∴z=2+6iz_0^81-3iz_0^93 =3+6i ( (z_0 )^3 )^27-3i ( (z_0 )^3 )^31 =3+6i-3i =3+3i ∴ arg (z ) tan^-1 ( 33 )= 4

$Let z_{0} be a root of a quadratic equation, x^{2} + x + 1 = 0 . If z = 3 + 6 i z_{0}^{81} - 3 i z_{0}^{93}, then arg z is equal to:$

Solution

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