If f (x )=x^2-2x+4, then the set of values of x satisfying f (x-1 )=f (x+1 ) is

Question

Accepted Answer

Correct answer: C. (c) We have, f (x )=x^2-2x+4 Now, f (x-1 )=f (x+1 ) (x-1 )^2-2 (x-1 )+4= (x+1 )^2-2 (x+1 )+4x^2-2x+1-2x+2+4=x^2+2x+1-2x-2+4 -4x=-4 ⇒x=1 ∴ Set of values of x ,x= 1 .

$If f (x) = x^{2} - 2 x + 4, then the set of values of x satisfying f (x - 1) = f (x + 1) is$

Solution

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