JEE Previous Year Questionlimn→∞(n34(n+1)31+n34(n+2)31+…+n34(2n)31) is equal to :Topic: JEE PYQAnswer: A. Full step-by-step solution below.A43(2)34−43B34(2)34C23(2)34−34D34(2)43Correct answer: ASolution(a) JEEN Main 2019limn→∞(n(n)31(n+1)31+(n+2)31+…+(n+n)31)=limn→∞∑n.n31(n+r)31=∑(1+x)31dx (∵nr→xandn1→xd)=(43(1+x)34)01=43(2)34−43More Definite Integration PYQsLet g(x)=∫0xf(t)dt, where f is continuous function in [0,3] such that 31≤f(t)≤1 for all…If ∫0K2+18x2dx=24π, then the value of K is∫041+x1dx=Let a differentiable function f satisfy f(x)+∫3xtf(t)dt=x+1, x≥3. Then 12f(8) is equal toThe value of the integral ∫−12loge(x+x2+1)dx is