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JEE Previous Year Question

$The value of 12 \int_{0}^{3} ∣ x^{2} - 3 x + 2∣ d x is ________$

Topic: JEE PYQ

Answer: 22. Full step-by-step solution below.

Correct answer: 22

Solution

(22) 12 \sum (x^{2} - 3 x + 2) dx = 12 \sum ((x - \frac{3}{2}) - \frac{1}{4}) dx If x = \frac{3}{2} = t dx = dt = 24 \sum (t^{2} - \frac{1}{4}) dt = 24 (- \sum (t^{2} - \frac{1}{4}) dt + \sum (t^{2} - \frac{1}{4}) dt]) = 22

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