JEE Previous Year Question∫01x(1−x)5dx=Topic: JEE PYQAnswer: B. Full step-by-step solution below.A1/5B1/42C1/13D13/42Correct answer: BSolution(b) : Let I=∫01x(1−x)5dx=−∫01(1−x−1)(1−x)5dx=−(∫01(1−x)6dx−∫01(1−x)5dx)=∫01(1−x)5dx−∫01(1−x)6dx=(−6(1−x)6)01−(−7(1−x)7)01=61−71=421More Definite Integration PYQsLet g(x)=∫0xf(t)dt, where f is continuous function in [0,3] such that 31≤f(t)≤1 for all…If ∫0K2+18x2dx=24π, then the value of K is∫041+x1dx=Let a differentiable function f satisfy f(x)+∫3xtf(t)dt=x+1, x≥3. Then 12f(8) is equal toThe value of the integral ∫−12loge(x+x2+1)dx is