The sum of the squares of the eccentricities of the conics x^24+ y^23=1 and x^24- y^23=1 is

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Correct answer: A. (a) : The equation of ellipse be x^24+ y^23=1 Eccentricity, e_1= 4-34= 12 Equation of hyperbola is x^24- y^23=1 Eccentricity, c_2= 4+34= 72 Now, c_1^2+c_2^2= 14+ 74= 84=2

$The sum of the squares of the eccentricities of the conics \frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1 and \frac{x ^{2}}{4} - \frac{y ^{2}}{3} = 1 is$

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