If x^2=8 ay is the transformed equation of x^2-4y+6x+15=0 when the origin is shifted to the point ( , ) by translation of axes, then 2 +8 ^2=

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Correct answer: C. (c) Translated equation of x^2-8 ay=0 is with point ( , ) is (x- )^2-8a (y- ) ≡x^2-4y+6x+15 (Given) ⇒x^2-8 ay-2 αx+ ^2+8 aβ=x^2-4y+6x+15 On comparing we get =-3 , = 32 and a= 12 Hence 2 +8 ^2=12

$If x^{2} = 8 ay is the transformed equation of x^{2} - 4 y + 6 x + 15 = 0 when the origin is shifted to the point (α, β) by translation of axes, then 2 α + 8 β^{2} =$

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