The distance between the foci of a hyperbola is 16 and its eccentricity is 2. Its equation is

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Accepted Answer

Correct answer: B. (b) : Let the equation of hyperbola be x^2a^2- y^2b^2=1 Distance between foci is 16. ∴2 ae=16 ⇒ 2a 2=16 ⇒a= 8 2=4 2 Also, e^2= a^2+b^2a^2 ⇒2= 32+b^232 ⇒b^2=64-32 ⇒b^2=32 ∴ Equation of hyperbola is x^232- y^232=1 ⇒x^2-y^2=32

$The distance between the foci of a hyperbola is 16 and its eccentricity is 2 . Its equation is$

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