The value of a, such that the power of the point (1 ,6 ) with respect to the circle x^2+y^2+4x-6y-a=0, is -16 , is

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Correct answer: D. (d) Given power of point P (16 ) w.r.t. the circle is -16 . ⇒S_1<0 Given equation of the circle is x^2+y^2+4x-6y-a=0 Hence, 1+36+4-36-a=-16 ⇒5-a=-16 ⇒a=21 .

$The value of a, such that the power of the point (1, 6) with respect to the circle x^{2} + y^{2} + 4 x - 6 y - a = 0, is -16 , is$

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