If 2 sin ⁡h^-1 ( a 1-a^2 )= log ⁡ ( 1+x1-x ), then x is equal to

Question

Accepted Answer

Correct answer: A. (a) Given, 2 sinh^-1 ( a 1-a^2 )= log ⁡ ( 1+x1-x ) Using sinh^-1y= log ⁡(y+ 1+y^2) we get 2 sinh^-1 ( a 1-a^2 )= log ⁡ ( 1+a1-a ) Comparing, 1+x1-x= 1+a1-a Hence, x=a

$If 2 sin h^{- 1} (\frac{a}{1 - a ^{2}}) = log (\frac{1 + x}{1 - x}), then x is equal to$

Solution

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