Let S=(x : cos^-1 ⁡x= + sin^-1 ⁡x+ sin^-1 ⁡ (2x+1 )). Then 0.05em (2x-1 )^2 is equal to .

Question

Accepted Answer

Correct answer: 5. (5) cos^-1 ⁡x= + sin^-1 ⁡x+ sin^-1 ⁡ (2x+1 ) 2 cos^-1 ⁡x- sin^-1 ⁡ (2x+1 )= 3 2 2 - = 3 2 where cos^-1 ⁡x= , sin^-1 ⁡ (2x+1 )= 2 = 3 2+ cos ⁡2 = sin ⁡ 2 cos^2 ⁡ -1= sin ⁡ 2x^2-1=2x+1 x^2-x-1=0 ⇒n= 1 52=(n= 1+ 52 rejedctedn= 1- 52) ∴4x^2-4x=4 (2x-1 )^2=5

$Let S = (x : cos^{- 1} x = π + sin^{- 1} x + sin^{- 1} (2 x + 1)) . Then \sum (2 x - 1)^{2} is equal to .$

Solution

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